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29 days ago

12

A 227 pound compressor is supported by four legs that contact the floor of a machine shop. At the bottom of each leg there is a

circular pad formed from a synthetic material to dampen vibration. The synthetic material will support up to a maximum pressure of 42 psi before deforming. What is the minimum diameter to avoid deforming the material?

1 answer:

choli [191]29 days ago

6 0

Answer:

1.312 in

Explanation:

The details provided in the question are:

The weight of the compressor, W is 227 pounds.

It has 4 legs.

The maximum permissible pressure is 42 psi.

Let F represent the force exerted by each leg.

Thus,

W = 4F,

or

227 pounds = 4F,

implying that:

F = 56.75 pounds.

Furthermore,

Force = Pressure × Area,

therefore:

56.75 pounds = 42 psi × πr² [ r signifies the radius of one leg]

Consequently, we find:

r² = 0.4301,

and thus:

r = 0.656;

resulting in a diameter equal to 2r = 2 × 0.656,

which equals 1.312 in.

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Explanation:

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Response:

The cutting speed is calculated at 365.71 m/min

Clarification:

Given parameters include

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To find

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Tc =

....................1

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Answer:

$m_{s}=20kg/min$

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Explanation:

A liquid food containing 12% total solids is heated via steam injection at a pressure of 232.1 kPa (see Fig. E3.3). The product starts at a temperature of 50°C and has a flow rate of 100 kg/min, being elevated to a temperature of 120°C. The specific heat of the product varies with its composition as follows:

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Product total solids out ( $X_{B}$ ) = 0.1

Product temperature in ( $T_{A}$ ) = 50°C

Product temperature out ( $T_{B}$ ) = 120°C

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Product specific heat in ( $C_{PA}$ ) = 3.936 kJ/(kg°C)

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$m_{A}X_{A}=m_{B}X_{B}$

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By substituting values into the energy equation:

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$H_{v}$ = 2713.5 kJ/kg

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