Six years ago, an 80-kW diesel electric set cost $160,000. The cost index for this class of equipment six years ago was 187 and
1 answer:
Answer:
total expense for the new boiler = $229706.825
total expense for new boiler = $127512
Explanation:
provided information
initial power p1 = 80 kW
price C = $160000
cost index CI 1 = 187
cost index CI 2= 194
capacity factor f = 0.6
subsequent power p2 = 120 kW
present cost = $18000
to determine
total expense and cost for 40 kW
solution
we evaluate CN cost for the new boiler and CO cost for the existing boiler
where x represents the capacity of the new boiler
first we compute the current cost of the old boiler which is
current cost CO = C × .............1
substituting the value here
current cost = 160000 ×
updated current cost = $165989.304
and
employing power sizing strategy for 124 kW
CN/CO = ...............2
insert value and calculate CN
CN/CO =
CN / 165989.304 =
CN = 211706.825
therefore the new expense = $211706.825
hence
total expense for the new boiler amounts to
total expense = new expense + current cost
total exp = 211706.825 + 18000
boiler expense total = $229706.825
and
concerning a 40 kW unit, the calculated new cost will be
applying equation 2
CN/CO =
CN / 165989.304 =
CN = 109512
thus the new cost is $109512
therefore
total expense for the new boiler is
total exp = new cost + current cost
total expense = 109512 + 18000
total cost for the new boiler = $127512
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Answer:
a) v₂ = 26.6 ft/s
b) v₂ = 31.9 ft/s
Explanation:
a) Applying the principle of energy conservation for the soccer arm from the point of impact to its lowest point:
The ball's velocity in the tangential direction is given by:
v₂*sinθ = v₁*sin30
With the values:
if v₁ = 0
θ = 0º
The restitution coefficient is:
where O=θ
The aggregate momentum equation is:
, where O = θ
When we incorporate gravitational acceleration:
Isolating v₂ results in:
v₂ = 26.6 ft/s
b) To find the ball's velocity, we utilize:
v₂ * sinθ = v₁ * sin30
if v₁ = 10 ft/s
then v₂ * sinθ = 10 * sin30
thus sinθ = 5/v₂
The restitution coefficient remains:
where O = θ
Solving for v₂ yields:
v₂ = 31.9 ft/s
Answer:
a) The phase before eutectoid is commonly referred to as cementite, with the chemical formula Fe₃C.
b) The total mass of ferrite obtained is 0.8311 kg.
The total cementite mass equals 0.1689 kg.
c) The total cementite mass accounts for 0.9343 kg.
Explanation:
Provided:
1 kg of austenite
a carbon content of 1.15 wt%
Cooled below 727°C
Questions:
a) Identify the proeutectoid phase.
b) Calculate the mass of total ferrite and cementite, Wf =?, Wc =?
c) Determine the mass of both pearlite and the proeutectoid phase, Wp =?
d) Create a schematic to illustrate the resulting microstructure.
a) The proeutectoid phase is referred to as cementite with the formula Fe₃C.
b) To find the total mass of formed ferrite:
With:
Ccementite = composition of cementite = 6.7 wt%
C₁ = composition of phase 1 = 0.022 wt%
C₂ = overall composition = 1.15 wt%
Inserting the values yields:
For the total mass of cementite:
c) The mass of pearlite:
d) The diagram illustrates the different compositions: (pearlite, proeutectoid cementite, ferrite, eutectoid cementite)
Answer:
Temperature T = 394.38 K
Explanation:
The full solution and detailed explanation regarding the above question and its specified conditions can be found below in the accompanying document. I trust my explanation will assist you in grasping this particular topic.
