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sweet-ann
1 month ago
12

A 0.20 kg mass on a horizontal spring is pulled back 2.0 cm and released. If, instead, a 0.40 kg mass were used in this same exp

eriment, the total energy of the system would A 0.20 mass on a horizontal spring is pulled back 2.0 and released. If, instead, a 0.40 mass were used in this same experiment, the total energy of the system would Be half as large. Double. Remain the same.
Physics
1 answer:
Keith_Richards [3.2K]1 month ago
8 0

Answer:

The total mechanical energy remains unchanged regardless of adjustments in mass. It stays consistent

Explanation:

In a spring-mass system, the collective mechanical energy equates to the elastic potential energy whenever the system is at amplitude. This can be defined as:

E=U=\frac{1}{2}kA^2       (1)

k: spring constant

A: amplitude of motion = 2.0cm

As reflected in equation (1), the total mechanical energy is independent of the object's mass; it solely relies on the amplitude A and the spring constant.

Therefore, whether you use a mass of 0.40kg or 0.20kg, the total mechanical energy remains constant.

Stays the same

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Explanation:

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R =

R_{o} + \alpha [T_{2} - T_{1}]

where,   R = final resistance

       

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= temperature coefficient of resistivity\alpha

       

= final temperature     T_{2}

       

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Given data as follows.

     

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Substituting the provided values into the above formula gives us the following.

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