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olga55
2 months ago
8

To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from

the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.337 m from rest
Physics
1 answer:
Sav [3.1K]2 months ago
7 0

Response:

The stone's velocity is 2.57 m/s.

Clarification:

Provided that

Height = 0.337 m

We need to determine the velocity of the stone

Using the motion equation

v^2-u^2=2gh

Where, v = velocity of the stone

u = initial velocity

g = gravity's acceleration

h = height

Substituting into the formula

v^2-0=2\times9.8\times 0.337

v=\sqrt{2\times9.8\times0.337}

v=2.57\ m/s

Thus, the stone's velocity is 2.57 m/s.

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A 2.1 × 103 kg car starts from rest at the top of a driveway that is sloped at an angle of 20.0° with the horizontal. An average
Keith_Richards [3271]

Answer:

The driveway measures 4.98 m

Explanation:

We aim to find the length of the driveway, thus utilizing the following equations

W=ΔK.E    where W represents work and  ΔK.E   indicates the change in kinetic energy

Moreover,

K.E = \frac{ MV^2}{2}also

W = F.d  where F is the force and d denotes distance

Given that

= 4000 N indicating this frictional force

F_{f} m = 2100 Kg  

θ= 20.0°  

V=3.8 m/s representing the car's speed at the bottom of the driveway

W=Δ K.E

=  15162  J  

W = (1/2)(2100)(3.8)^2As the x component of gravity is

= mg sinФ

Fx_thus

= (2100)(9.8)sin(20.0°) results in

Fx_{} = 7038.77 N

And the Net force isFx_{}

=

-

F_{net}Fx_ {} = 7038.77 - 4000 = 3038.77 NF_{f}

So, the length of the driveway equals W / (

) = 15162/3038.77 = 4.98 m F_{net}

F_{net}

Thus, this is the length of the driveway.

3 0
2 months ago
Narrow, bright fringes are observed on a screen behind a diffraction grating. The entire experiment is then immersed in water. D
Ostrovityanka [3204]

Response:

n (a sin θ) = m λ₀

Since n > 1, this indicates that the fringes separate further apart

Clarification:

In a diffraction experiment, the equation for constructive interference fringes is provided by

a sin θ = m λ₀

It is presumed that the air has been evacuated from the experiment, setting n = 1

When this experiment is conducted in water, the wavelength alters

λₙ = λ₀ / n

for achieving constructive interference

a sin θ = m λₙ

we replace

a sin θ = m λ / n

n (a sin θ) = m λ₀

Given that water's refractive index is n = 1.33, the distance between the fringes increases due to n > 1, causing the fringes to move apart

8 0
2 months ago
Determine the torque applied to the shaft of a car that transmits 225 hp
Keith_Richards [3271]

Incomplete query. The complete inquiry is as follows

Calculate the torque exerted on the shaft of a vehicle transmitting 225 hp at a rotation speed of 3000 rpm.

Response:

Torque=0.51 Btu

Analysis:

Given Information

Power=225 hp

Revolutions =3000 rpm

To determine

T( torque )=?

Process

As an object is moved by force over a distance, work is performed on that object. Similarly, when torque rotates an object through an angle, work is also accomplished.

T(Torque)=\frac{W(Work)}{2\pi n(Revolutions) }

8 0
3 months ago
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