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olga55
1 month ago
8

To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from

the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.337 m from rest
Physics
1 answer:
Sav [3.1K]1 month ago
7 0

Response:

The stone's velocity is 2.57 m/s.

Clarification:

Provided that

Height = 0.337 m

We need to determine the velocity of the stone

Using the motion equation

v^2-u^2=2gh

Where, v = velocity of the stone

u = initial velocity

g = gravity's acceleration

h = height

Substituting into the formula

v^2-0=2\times9.8\times 0.337

v=\sqrt{2\times9.8\times0.337}

v=2.57\ m/s

Thus, the stone's velocity is 2.57 m/s.

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Keith_Richards [3271]

Utilizing the same generator, the only variable affecting the electric field is the speed. The higher the generator's rotation speed, the more extensive the electric field it generates. Hence, the order is 3000 rpm<3200 rpm<3400 rpm<3600 rpm

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An electron moves in a region where the magnetic field is uniform and has a magnitude of 80 μT. The electron follows a helical p
Softa [3030]

Answer:

3.4 x 10⁴ m/s

Explanation:

Analyze the circular path of the electron

B = magnetic field = 80 x 10⁻⁶ T

m = mass of an electron = 9.1 x 10⁻³¹ kg

v  = speed in the radial direction

r = radius of the circular trajectory = 2 mm = 0.002 m

q = charge of an electron = 1.6 x 10⁻¹⁹ C

For the electron’s circular movement

qBr = mv

(1.6 x 10⁻¹⁹) (80 x 10⁻⁶) (0.002) = (9.1 x 10⁻³¹) v

v = 2.8 x 10⁴ m/s

Now, consider the electron's movement in a straight line:

v' = speed in linear motion

x = distance traveled horizontally = 9 mm = 0.009 m

t = duration = \frac{2\pi m}{qB} = \frac{2\pi (9.1\times 10^{-31})}{(1.6\times 10^{^{-19}})(80\times 10^{-6})} = 4.5 x 10⁻⁷ sec

Using the formula

x = v' t

0.009 = v' (4.5 x 10⁻⁷)

v' = 20000 m/s

v' = 2 x 10⁴ m/s

The resultant speed is given by

V = sqrt(v² + v'²)

V = sqrt((2.8 x 10⁴)² + (2 x 10⁴)²)

v = 3.4 x 10⁴ m/s

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1 month ago
A rope connects boat A to boat B. Boat A starts from rest and accelerates to a speed of 9.5 m/s in a time t = 47 s. The mass of
ValentinkaMS [3465]

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Given data:

Time (t) = 47s

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Final speed (V) = 9.5m/s

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Since both boats are linked, movement of A causes B to move as well.

What is the acceleration of boat A?

Applying the motion formula:

V = u + at

9.5 = 0 + a * 47

a = 9.5 / 47

a = 0.2021 m/s²

To determine the force necessary to accelerate boat B, as both boats experience the same force:

F = Mass * acceleration

F = 540 * 0.2021 = 109.14N

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In what processes do proteins in the electron transport chain participate?
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Answer:

1. Reactions involving oxidation and reduction along with proton pumping

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