Answer:
The third-order dark fringe
Explanation:
y = Distance from central bright fringe = 204 mm
λ = Wavelength = 400 nm
L = Distance from screen to source = 1 m
d = Slit spacing = 6 μm
The order of the fringe is 3
Thus, it’s identified as a dark fringe.
To find the mass using a weight of 1.4 N:
1.4/9.8 = 0.1428 kg
The momentum is calculated as 0.1428 multiplied by 44.7, which is 6.38 kgm/s.
The solution leads to the conclusion that m1 = m2
For mass m1, the force balance in the y direction equals zero:
0 = T - m1*g
Rearranging gives:
m1*g = T
For mass m2, the force balance in the y direction equals zero:
0 = T - m2*g
Rearranging provides:
m2*g = T
Setting these two equal allows us to solve for m1:
m1*g = m2*g
= m1 = m2
Explanation:
The force acting on each individual mass pulls down while the tension created by the other mass exerts an upward force due to the operation of the pulley system, resulting in balanced forces on both masses.
Answer:
The velocities of both 
-mesons are 0.574 in the positive direction and -0.9367c in the negative direction along the X-axis
Solution:
Referring to the question:
The speed of the -meson is v' = 0.828c
And the K-meson's speed in the positive x direction is v'' = 0.486c
Now, to determine the speeds of the two -mesons:
Velocity of the first
-meson,
:
Velocity of the second -meson, :
