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8 days ago
7

When numbers are very small or very large, it is convenient to either express the value in scientific notation and/or by using a

prefix with the unit. A pain-relieving pill has a mass of 0.005 g. Express the pill’s mass in grams using scientific notation or in milligrams. Express your answer in scientific notation to one significant figure or use a prefix on the unit.
Physics
1 answer:
Maru [2.9K]8 days ago
4 0

Answer:

5 mg, 5\cdot 10^{-3}g

Explanation:

First, we should express the mass in grams using scientific notation.

so we find:

m = 0.005 g

To convert it into scientific notation, we observe that we have to shift the decimal three places to the right. Hence in scientific notation it becomes

m=5\cdot 10^{-3}g

Converting to milligrams, we must remember that

1 g = 1000 mg

Thus we can set up the ratio

1 g: 1000 mg = 0.005 g: x

and we conclude with

x=\frac{(1000 mg)(0.005 g)}{1 g}=5 mg

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Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e., the length and radius have twice th
Softa [2668]

Response:

The new resistance is half of the original resistance.

Explanation:

Resistance in a wire is represented by:

R=\dfrac{\rho L}{A}

\rho = resistivity of the material

L and A are the physical dimensions

If a wire is exchanged for one where all linear dimensions are doubled, i.e. l' = 2l and r' = 2r

The updated resistance of the wire can be calculated as follows:

R'=\dfrac{\rho L'}{A'}

R'=\dfrac{\rho (2L)}{\pi (2r)^2}

R'=\dfrac{1}{2}\dfrac{\rho L}{A}

R'=\dfrac{1}{2}R

The new resistance equals half of the original resistance. Thus, this provides the solution needed.

4 0
20 days ago
A small object slides along the frictionless loop-the-loop with a diameter of 3 m. what minimum speed must it have at the top of
ValentinkaMS [3097]
<span>3.834 m/s. To solve this problem, we must ensure that the centripetal force equals or exceeds the gravitational force acting on the object. The formula for centripetal force is F = mv^2/r while the equation for gravitational force is F = ma. Since the mass (m) cancels out in both equations, we can equate them, leading to a = v^2/r. Now, inserting the given values (where the radius is half the diameter) allows us to find v: 9.8 m/s^2 <= v^2/1.5 m, which simplifies to 14.7 m^2/s^2 <= v^2. Therefore, we find that the minimum velocity required is 3.834057903 m/s <= v. Thus, the necessary speed is 3.834 m/s.</span>
4 0
26 days ago
A metal, M, forms an oxide having the formula M2O3 containing 52.92% metal by mass. Determine the atomic weight in g/mole of the
ValentinkaMS [3097]

Answer:

The molar mass of the metal in grams per mole is calculated to be 8.87.

Explanation:

Initially, we can consider a sample of the compound weighing 100 g. This results in:

  • 52.92% metal: 52.92 g M
  • 47.80% oxygen: 47.80 g O

 By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

moles of oxygen=\frac{47.8g*1mol}{16g}

moles of oxygen=2.9875

The formula for the metal oxide indicates that:

2 M⁺³ + 3 O²⁻ ⇒ M₂O₃

From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

2.9875 moles of oxygen*\frac{2 moles of metal M}{1 mol of oxygen} = 5.975 moles of metal M

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass=\frac{52.92 g}{5.975 mol}

molar mass≅ 8.87 g/mol

The molar mass of the metal in grams per mole is 8.87.

The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.

3 0
16 days ago
A crate with a mass of m = 450 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate a
Sav [2836]

Answer:F_{v} =\mu_{k} mg

The force required has a magnitude of 2601.9 N

Explanation:

m = 450 kg

Static friction coefficient μs = 0.73

Kinetic friction coefficient μk = 0.59

The force necessary to initiate movement of the crate is F_{s} =\mu_{s} mg.

Once the crate begins to move, the frictional force decreases to F_{v} =\mu_{k} mg.

To maintain the motion of the crate at a steady velocity, we must lower the pushing force to F_{v} =\mu_{k} mg.

Subsequently, the pushing force aligns with the frictional force stemming from kinetic friction, enabling balanced forces and consistent velocity.

<pMagnitude of the force

F_{v} =\mu_{k} mg\\F_{v} =0.59 \times 450 \times 9.8\\F_{v} =2601.9 N

4 0
1 month ago
A student observes that for the same net force heavier objects accelerate less which statement describes the correct conclusion?
inna [2740]

Answer: Reduced acceleration leads to an increase in mass.

Explanation:

We can rephrase this as:

"When a constant force F is applied, heavier objects experience less acceleration"

As a result, when mass rises, the object's acceleration diminishes.

This is referred to as an inverse correlation between acceleration and mass.

According to Newton's second law, we find that:

F = m*a

Force equals mass multiplied by acceleration.

So, if the force remains constant, we can express it as:

a = F/m.

In this equation, we observe that if acceleration decreases and F stays constant, then the mass m must also rise (as it is found in the denominator)

Therefore, the accurate statement is:

A decrease in acceleration causes the mass to increase.

4 0
16 days ago
Read 2 more answers
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