The acceleration due to gravity on the moon is 1.6 m/s2, about a sixth that of Earth’s. Which accurately describes the weight of

Answer:

1. At 12:00, the hour hand is positioned at 0 degrees, with its tip moving at an estimated 1.26 cm/hour.
2. At 12:15, the minute hand is at 90 degrees, traveling at roughly 23.88 cm/hour.

Explanation:

The position is established by an angle, which begins at the 12:00 point and extends clockwise.

1. At noon, the hour hand is at the 12:00 position, thus its position is 0 degrees; it has an angular velocity of (2π)/(12 hours) = π/(6 hours). Therefore, the tip moves at a linear velocity of (2.4 cm) * π/(6 hours) ≅ 1.26 cm/hour.

1. At 12:15, the minute hand is at the 3 o'clock position, giving it a position of 90 degrees or π/2; its angular velocity is (2π)/(1 hour) = 2π/hour. Thus, the tip moves at a linear velocity of (3.8 cm) * 2π/hour ≅ 23.88 cm/hour.

Answer:

The resultant torque is zero.

Explanation:

Assuming the dipole consists of two equal but opposite charges e, it can be represented by a rod with one end featuring a charge e and the other end with -e. Since the dipole is aligned with the electric field, both charges experience forces that are parallel to this electric field. Consequently, there are no force components that act perpendicular to the rod, which is necessary for torque to occur.

Result:

1.60 g

Elucidation:

Based on the attached document:

we can infer that:

The distance covered in 2 seconds will be:

x = vt

x = 20 m/s × 2 s

x = 40 m

The segment corresponds to a quarter of a circle with radius r,

therefore, if 2 πr = 4 x

Then the radius (r) can be calculated as:

r = 25.5 m

Centripetal acceleration can be expressed as:

thus;

a = 15.7 m/s²

The acceleration magnitude suffered by your passengers in relation to the acceleration due to gravity can be calculated using:

∴ The acceleration magnitude experienced by your passengers while turning = 1.60 g

As the plane heads toward Halifax, the wind speed supports the flight path

resulting in an overall improved speed

Conversely, during the return trip, the wind will resist the plane's motion, decreasing the net speed

The total journey lasts 13 hours

of which 2 hours was dedicated to the mathematics discussion

Consequently, the total flight time is 13 - 2 = 11 hours

Now we apply the formula to calculate the time for traveling to Halifax

Time needed to return

Let’s look at the total time

By solving the derived quadratic equation

the plane's speed calculates to 550 mph

Answer:

Q = 12.5 kJ

Explanation:

The formula used to compute heat is:

Q = H° * n

Where:

Q: heat (J or kJ)

H°: enthalpy of reaction (kJ/mol)

n: moles

Now, as noted in the comments, the question lacks completeness, here is the part that is missing:

Given:

2A + B  A2B (1)

ΔH° = – 25.0 kJ/mol

2A2B  2AB + A2 (2)

ΔH° = 35.0 kJ/mol

Using these two reactions, we can determine the heat change.

Using the above two reactions, we need to establish the overall reaction (the one presented in the question), so let’s combine (1) and (2):

2A + B -------> A2B   H°1 = -25 kJ/mol

2A2B --------> 2AB + A2   H°2 = 35 kJ/mol

When we add these equations, one A2B cancels out with one A2B from reaction 2, thus, we have:

2A + B + 2A2B -------> 2AB + A2

So, for the enthalpy, the values are summed:

H°3 = -25 + 35 = 10 kJ/mol

Now we can calculate the heat:

Q = 10 * 2.5 = 25 kJ

However, as we have 2A in the reaction, it does not maintain a 1:1 mole ratio, instead, it is 1:2, which requires us to adjust; thus:

Q = 25 / 2 = 12.5 kJ