Answer:
The required energy remains identical in both scenarios since the specific heat capacity (Cp) does not change with varying pressure.
Explanation:
Given;
initial temperature, t₁ = 50 °C
final temperature, t₂ = 80 °C
Temperature change, ΔT = 80 °C - 50 °C = 30 °C
Pressure for scenario one = 1 atm
Pressure for scenario two = 3 atm
The energy needed in both scenarios is expressed as;
Where;
Cp denotes specific heat capacity, which only varies with temperature and remains unaffected by pressure.
Hence, the energy required remains the same for both scenarios since specific heat capacity (Cp) is pressure-independent.
Answer:
Explanation:
Let T represent the tension in the swing.
At the peak 
where v denotes the velocity needed to maintain the circular motion.
r equals the distance from the rotation point to the center of the ball, which is L+\frac{d}{2} (with d being the ball's diameter).
The threshold velocity can be expressed as 
To determine the velocity at the bottom, we can use energy conservation principles at both the top and bottom positions.
At the top 
Energy at the bottom 
By comparing the two states using conservation of energy, we find 
Response:
C. vx
F. ax
G. ay
Clarification:
The projectile follows a curved trajectory toward the ground, causing changes in x and y positions.
Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.
The projectile is subject to the force of gravity, directed downwards, leading to an increase in its velocity due to the rise in its y-component.
Meanwhile, the y-component of acceleration remains constant due to gravitational acceleration.
Answer: The calorimeter's heat capacity is 
Explanation:
This scenario assumes the amount of heat lost by the hot object equals the amount of heat gained by the cold object.
where,
= specific heat capacity of water = 
= specific heat capacity of calorimeter =?
= mass of water = 108.7 g
= mass of calorimeter = 108.7 g
= final temperature of the mixture = 
= initial temperature of the water = 
= initial temperature of calorimeter = 
Now substituting all provided values into the formula, we obtain
Hence, the heat capacity of the calorimeter is
Answer:
I do not communicate in Spanish
Explanation:
