Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
1 answer:
Answer:
b) TA = TB = TC
Explanation:
- When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
- During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
- The equilibrium state will be established once this equation is satisfied:
- Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:
- At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
- When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
- Therefore, option b) is correct.
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Answer:
a)
b)
c)
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.
(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.
Utilizing in our first equation (1)
Now let’s solve for t.
The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.
b) To determine the velocity magnitude just before impact, we must calculate both x and y components.
The computed velocity magnitude is:
c) The ball's angle is:
Answer:
d) v1 = v2 = v3
Explanation:
This can be determined through the principle of energy conservation. We assess the total mechanical energy E=K+U (the sum of kinetic energy and gravitational potential energy) at both the initial and final positions, ensuring they remain constant.
<pInitially, for the three spheres, we have:Finally, for the three spheres, we see:
Answer:
Explanation:
In this scenario, we determine the initial velocity as follows:
The final velocity in this instance can be expressed as:
It is noted that transitioning from 7m/s to 13m/s takes 8 seconds. We can apply a specific kinematic equation to find the acceleration for the first part of the journey:
Solved for acceleration, we find:
For the subsequent route, we assume constant acceleration and that the train continues for 16 seconds, beginning with an initial velocity of 13m/s from the previous segment, allowing us to calculate the final speed via the following formula:
Substituting into the equation yields: