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almond37
6 days ago
13

A group of engineers has created a biodome filled with air, plants, and animals. No material can get in or out, but sunlight can

get in during the daytime.
The walls of the biodome are made of a material that absorbs and locks away carbon dioxide from the air so it is not available to the living things inside. What do you predict will happen to carbon in the air over time? How could this affect the living things in the dome? Explain your thinking.
Chemistry
1 answer:
eduard [2.5K]6 days ago
6 0
I appreciate the points haha
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What stress will shift the following equilibrium system to the right? 2SO2(g) + O2(g) ⇌ 2SO3(g); ΔH= –98.8 kJ/mol Decreasing con
Alekssandra [2711]

Answer:

Lowering the temperature.

Explanation:

  • According to Le Châtelier's principle, when an equilibrium is disturbed by an outside influence, the system reacts by shifting in the direction that counteracts that disturbance and restores balance.
  • Let's analyze the given options:

1) Reducing the concentration of SO₂,

A decrease in SO₂ concentration causes the reaction to move leftward to compensate for this drop.

2) Lowering the temperature,

Given ΔH = –98.8 kJ/mol, which implies the reaction releases heat and is exothermic.

Dropping the temperature means there's less heat, prompting the equilibrium to shift right to produce more heat and offset the change.

This is the correct option.

3) Increasing SO₃ concentration,

An increase in SO₃ shifts the reaction left to reduce the SO₃ levels.

4) Raising the volume,

Increasing volume lowers the pressure, causing the equilibrium to shift towards the side with more gas moles—that is, the left side.

  • Therefore, decreasing the temperature is the correct choice.
3 0
1 month ago
A 8.5-liter sample of a gas has 1.2 mole of the gas. If 0.65 mole of the gas is added, what is the final volume of the gas? Temp
Alekssandra [2711]

Answer: 13 liters

Explanation: It is crucial to remember two factors that allow us to carry out this calculation.

Firstly, temperature and pressure must remain unchanged, so these constant values are not considered when calculating volume since they will always be the same.

Secondly, we are dealing with the same gas, with the conditions remaining consistent. Hence, we can proceed.

For 1.2 moles of gas, we have a volume of 8.5 liters. Now, let's determine the volume for 0.65 moles:

0.65 mole * (8.5 liter / 1.2 mole) = 4.25 liters

As we maintain the same gas type, we simply need to total the volumes for each mole amount:

8.5 liters + 4.25 liters = 12.75 liters, which rounds to 13 liters.

7 0
1 month ago
Read 2 more answers
A magnesium ion, Mg2+, with a charge of 3.2×10−19C and an oxide ion, O2−, with a charge of −3.2×10−19C, are separated by a dista
eduard [2509]

Details:

The equation to calculate work done is defined as follows.

W = -k \frac{q_{1}q_{2}}{d}

where, k = proportionality constant = 8.99 \times 10^{9} Jm/C^{2}

q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C

q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C

d = separation distance = 0.45 nm = 0.45 \times 10^{-9} m

Now we will insert the given values into the formula above to compute the work done as follows.

W = -k \frac{q_{1}q_{2}}{d}

= \frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}

= 3.68 \times 10^{-18} J

Thus, we can conclude that the work needed to increase the distance between the two ions to infinity is 3.68 \times 10^{-18} J.

7 0
20 days ago
How would a flood be a limitation for synthetic polymers that rely on natural rubber in its production?
eduard [2509]
A flood that affects the environment where natural rubber is produced would severely hinder rubber production. In order to greatly limit production, a flood would need to destroy a significant portion of rubber trees. Natural rubber is crucial for manufacturing synthetic polymers. If the rubber supply is compromised (due to the disruption of its ecosystem caused by a flood), there would be a substantial decline in the availability of synthetic polymers.


hope this helps
3 0
19 days ago
Read 2 more answers
Consider butter (density= 0.860 g/mL) and sand (density= 2.28 g/mL). If 1.00 mL of butter were mixed with 1.00 mL of sand and mi
Anarel [2600]

The mixture’s density is 1.57 g/cm³.


Step 1: Determine the mass of the butter.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{0.680 g} }{\text{1 cm}^{3 }} = \text{0.860 g}\\

Step 2: Determine the mass of the sand.


\text{Mass} = \text{1.00 cm}^{3 } \times \frac{\text{2.28 g} }{\text{1 cm}^{3 }} = \text{2.28 g}\\

Step 3: Determine the density of the mixture.

Total mass = 0.860 g + 2.28 g = 3.14 g.

Total volume = 1 cm³ + 1 cm³ = 2 cm³

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{\text{3.14 g} }{\text{2 cm}^{3 }} = \textbf{1.57 g/cm}{^{3}\\

6 0
1 month ago
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