Response:
V1 = 20.3L
Clarification:
P2 = 811.4Pa
V2 = 25.6L
P1 = 1023.6Pa
V1 =?
To answer this query, we will utilize Boyle's law, which states that the volume of a gas at constant temperature is inversely related to its pressure.
In mathematical terms,
V = k / P, where k = PV
The relationship can be defined as P1 × V1 = P2 × V2 = P3 × V3 =......=Pn × Vn
This simplifies to P1 × V1 = P2 × V2
Let’s rearrange for V1
V1 = (P2 × V2) / P1
Substituting values gives
V1 = (811.4 × 25.6) / 1023.6Pa
So, V1 = 20771.84 / 1023.6
This results in V1 = 20.29L, rounded to 20.3L
The energy released results in a kinetic energy of 92.2 keV for the products. We should convert keV into Joules, noting that 1 keV equals a kiloelectron volt. The required conversion is: 1.602×10⁻¹⁹ <span>joule = 1 eV
Kinetic energy = 92.2 keV * (1,000 eV/1 keV) * (</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules
Next, we can determine the velocity of each He atom from the kinetic energy:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
This solves to give us: v = 5.367×10¹¹ m/s
Answer:
1984
Explanation:
Utilizing the equation;
0.693/t1/2 = 2.303/t log (Ao/A)
Where;
t1/2 = half-life of the radioactive isotope
t= age of the wine
Ao= initial activity of the wine
A= activity at time = t
Substituting values, we have 0.693/12.3 = 2.303/t log (5.5/0.688)
0.693/12.3 = 2.079/t
0.056 = 2.079/t
t= 2.079/0.056
t= 37 years
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Answer:
Explanation:
Greetings,
According to the provided chemical equation, the production of 31.2 mL of hydrogen allows one to calculate its moles using the ideal gas equation as detailed below:
Since the ratio of hydrogen to magnesium is 1:1, its milligrams are derived through the following proportional factor calculation:
Regards.
Convert HCl and H2O to moles.
36.0 g of HCl = 0.987 moles HCl
98.0 g of H2O = 5.44 moles H2O
Based on the stoichiometric ratio for HCl,
there are 0.987 moles of H and 0.987 moles of Cl.
For H₂O, according to the stoichiometric ratio, you have 10.88 moles of H and 5.44 moles of O.
Combining them:
11.867 moles H
0.987 moles Cl
5.44 moles O
Revert the moles back to grams, then divide by the total mass and multiply by 100 for the percentage by mass.
11.867 moles H = 11.96 g H
0.987 moles Cl = 34.99 g Cl
5.44 moles O = 87.03 g O
11.96/(36.0+98.0)(100) = 8.93% for H
34.99/(36.0+98.0)(100) = 26.11% for Cl
87.03/(36.0+98.0)(100) = 64.96% for O.
