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aniked
2 months ago
11

An industrial manufacturer wants to convert 175 kg of methane into HCN. Calculate the masses of ammonia and molecular oxygen req

uired for this synthesis.
Chemistry
1 answer:
Alekssandra [3K]2 months ago
4 0
Context:

175 kilograms of methane (CH4) is to be converted into hydrogen cyanide (HCN)

The equation that balances this reaction is listed here:

2 CH4<span> + 2 NH</span>3<span> + 3 O</span>2<span> → 2 HCN + 6 H</span>2<span>O
</span>
To find the quantities of ammonia and oxygen needed, we will use 175 kg of CH4 as our reference.

Molar masses are as follows:
CH4 = 16 kg/kmol
NH3 = 17 kg/kmol
O2 = 32 kg/kmol

For ammonia: mass of NH3 = 175 kg CH4 / 16 kg/kmol * (2/2) * 17 kg/kmol  
This results in 185.94 kg of NH3 required

For oxygen: mass of O2 = 175 kg CH4 / 16 kg/kmol * (3/2) * 32 kg/kmol
So the mass of O2 needed equals 525 kg

To derive the mass of oxygen: mass of O = 525 kg / 32 kg/kmol * (1/2) * 16 kg/kmol
This gives a mass of O equal to 131.25 kg O 
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From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH
lions [2927]

Answer: KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Explanation:

Ionic compounds form when one atom transfers its valence electrons to another atom, resulting in partial opposite charges on the participating atoms, which creates a strong attractive force between them.

An ionic bond is typically established between a metal and a non-metal.

For instance, KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Conversely, a covalent compound arises through the sharing of electrons among the atoms involved, where generally a non-metal bonds with the same or another non-metal.

For example, POCl_{3}, SOCl_{2} etc are all covalent compounds.

Therefore, we can affirm that KOCH_2CH_3, [tex]CH_3CH_2COONa, NaOH are indeed ionic compounds.

4 0
2 months ago
It is 762 miles from here to Chicago. An obese physics teacher jogs at a rate of 5.0 miles every 20.0 minutes. How long would it
Anarel [2989]
3,048 minutes. Explanation: 762 divided by 5, then multiply that number by 20.
5 0
1 month ago
In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat
alisha [2963]

Answer: 1.14

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

To find the molarity of the acid, we will utilize the equation derived from the neutralization process:

n_1M_1V_1=n_2M_2V_2

where

are the n-factor, molarity, and volume for the acid and

represent the n-factor, molarity, and volume for NaOH.

We know that:n_1,M_1\text{ and }V_1HCl

By substituting the known values into the equation, we get:

n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL

To determine the pH of gastric juice:

The molarity amounts to = 0.072

1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M

Thus, the pH level of the gastric juice is 1.14

3 0
2 months ago
Suppose you wanted to make a buffer of exactly ph 7.00 using kh2po4 and na2hpo4. if the final solution was 0.10 m in kh2po4, wha
Tems11 [2777]
The answer is - 0.138 M. The buffer pH can be determined using the Henderson equation. Here, KH_2PO_4 acts as a weak acid and Na_2HPO_4 serves as its corresponding conjugate base. The weak acid has two protons, while the base contains one. The equation can therefore be expressed in terms of protons transferred. Phosphoric acid can donate protons in three stages; the equation we’ve referenced pertains to the second stage, as the acid then has only two protons available and the base only one. Given the concentration of the acid as 0.10 M, we need to calculate the concentration of the base necessary to form a buffer with a pH of exactly 7.0. Substituting the values into the equation leads us to the solution. Cross-multiplying, we find that [base] = 1.38(0.10), yielding [base] = 0.138. Therefore, the concentration of the base needed for the buffer is 0.138 M.
5 0
1 month ago
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