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OleMash
1 month ago
7

"A sample of silicon has an average atomic mass of 28.084amu. In the sample, there are three isotopic forms of silicon. About 92

.22% of silicon atoms are 27.9769amu, which have the mass of 28Si; about 4.68% are 28.9764amu, which have the mass of 29Si, and the remaining isotope, 30Si, has a mass of 29.9737amu. Calculate the percent isotopic composition of 30Si."
Chemistry
1 answer:
lorasvet [2.7K]1 month ago
6 0

Answer: The percentage abundance for _{14}^{30}\textrm{Si} isotope is 3.09 %.

Explanation:

The average atomic mass of an element is calculated by taking the sum of the masses of all isotopes weighted by their respective natural fractional abundances.

To compute average atomic mass, the following formula is applied:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

From the information provided:

Let the fractional abundance for _{14}^{28}\textrm{Si} isotope be 'x'

  • For _{14}^{28}\textrm{Si} isotope:

Mass of _{14}^{28}\textrm{Si} isotope = 27.9769 amu

Percentage abundance of _{14}^{28}\textrm{Si} isotope = 92.22 %

Fractional abundance for _{14}^{28}\textrm{Si} isotope = 0.9222

  • For _{14}^{29}\textrm{Si} isotope:

Mass of _{14}^{28}\textrm{Si} isotope = 28.9764 amu

Percentage abundance for _{14}^{28}\textrm{Si} isotope = 4.68%

Fractional abundance of _{14}^{28}\textrm{Si} isotope = 0.0468

  • For _{14}^{30}\textrm{Si} isotope:

Mass of _{14}^{30}\textrm{Si} isotope = 29.9737 amu

Fractional abundance for _{14}^{30}\textrm{Si} isotope = x

  • The average atomic mass of silicon is 28.084 amu

By inserting these values into equation 1, we derive:

28.084=[(27.9769\times 0.9222)+(28.9764\times 0.0468)+(29.9737\times x)]\\\\x=0.0309

To convert this fractional abundance into a percentage, multiply by 100:

\Rightarrow 0.0309\times 100=3.09\%

This shows that the percentage abundance for _{14}^{30}\textrm{Si} isotope is 3.09 %.

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How many atoms of Mg are present in 97.22 grams of Mg?
VMariaS [2998]

Answer: The correct choice is (b).

Explanation:

We have the mass of Magnesium at 97.22 g, and the molar mass of Magnesium is 24.305 g/mol.

Therefore, the calculation for the number of moles is as follows.

          Number of moles = \frac{mass given in grams}{Molar mass}

                                 = \frac{97.22 g}{24.305 g/mol}  

                                 = 4 mol

Additionally, it is known that one mole contains 6.023 \times 10^{23} atoms/mol. Thus, we calculate the total number of atoms in 4 moles as follows.

               4 mol \times 6.023 \times 10^{23} atoms/mol

               = 24.08 \times 10^{23} atoms

or,            = 2.408 \times 10^{23} atoms

Hence, we conclude that in 97.22 grams of Magnesium, there are 2.408 \times 10^{23} atoms.

7 0
1 month ago
Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is a, the current ratio
Alekssandra [3086]
N₀ signifies the quantity of C-14 atoms per kg of carbon in the original sample at time = 0 seconds, when the carbon composition matched that in today’s atmosphere. As time progresses to ts, the number of C-14 atoms per kg declines to N, due to radioactive decay. λ indicates the decay constant.
Hence, we have N = N₀e - λt, which is the equation for radioactive decay. Rearranging gives us N₀/N = e λt, or In(N₀/N) = - λt, which becomes equation 1.
The sample contains mc kg of carbon, leading to an activity measured as A/mc decay per kg. The variable r represents the initial mass of C-14 in the sample at t=0 relative to the total mass of carbon which is calculated as [(total number of C-14 atoms at t = 0) × ma] / total mass of carbon. Thus, N₀ equates to r/ma, which becomes equation 2.
The activity of the radioactive element is directly related to the atom count at the moment. The activity equation A = dN/dt = λ(N) indicates that: A = λ₁(N × mc). Rearranging provides N = A / (λmc), represented in equation 3.
By integrating equations 2 and 3, we can solve for t yielding
t = (1/λ) In(rλmc/m₀A).

6 0
1 month ago
Select all the element(s) from the periodic table shown that will form an ionic compound with a metal M and a nonmetal X and a f
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Response:

Sulfate- SO4^2-

Sulfite- SO3^2-

Permanganate- MnO4

Carbonate- CO3^2

Clarification:

KEEP GOING WITH YOUR STUDIES!

4 0
1 month ago
When the concentration of solute in a solid solution exceeds its solubility limit, a new solid solution or phase forms that has
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8 0
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Oxygen at 150 k and 41.64 atm has a tabulated specific volume of 4.684 cm3/g and a specific internal energy of 1706 j/mol. calcu
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Specific enthalpy is defined as the overall energy in a system attributed to its temperature and pressure, measured per unit mass. It is essential in thermodynamic calculations when one needs to determine the energy for a specific unit mass of a component.

Specific enthalpy can be computed with the equation:

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For this example, the specific volume is 4.684 cm³/g or 149.888 cm³/g moles, which translates to 149.888 × 10⁻³ J/g moles.

The specific internal energy (U) is 1706 J/mol, and the pressure measured is 41.64.

Calculating gives us H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules

= 2428 joules / mole


5 0
1 month ago
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