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zvonat
22 days ago
6

Silver is often extracted from ores such as k[ag(cn)2] and then recovered by the reaction 2k ⎡ ⎣ag(cn)2 ⎤ ⎦(aq) + zn(s) ⟶ 2ag(s)

+ zn(cn)2 (aq) + 2kcn(aq) (a) how many molecules of zn(cn)2 are produced by the reaction of 35.27 g of k[ag(cn)2]? (b) what mass of zn(cn)2 is produced?
Chemistry
1 answer:
castortr0y [3K]22 days ago
5 0
Be mindful of the integer next to each chemical in the equation, as these will be necessary for the stoichiometric calculations that follow:

Molar mass of <span>k[ag(cn)2]: 199 g/mol
Molar mass of Zn(Cn)2: 117.44 g/mol
Avogadro's number: 6.022</span>×10²³ molecules/mol

a.)

35.27 g*(1 mol/199 g)*(1 mol Zn(Cn)₂/ 2 mol K[Ag(CN)₂])*(6.022×10²³ molecules/mol) = 5.34×10²² molecules of Zn(Cn)₂

b.)

35.27 g*(1 mol/199 g)*(1 mol Zn(Cn)₂/ 2 mol K[Ag(CN)₂])*(117.44 g/mol) = 10.41 g of Zn(Cn)₂
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In a car piston shown above, the pressure of the compressed gas (red) is 5.00 atm. If the area of the piston is 0.0760 m^2. What
Anarel [2989]

Answer:

The force is 38503.5N.

Explanation:

From the problem, we determine:

P (pressure) = 5.00 atm.

Next, to find the force in Newtons (N), we must convert 5 atm into N/m², as shown:

1 atm equals 101325 N/m².

So, 5 atm equals 5 x 101325 = 506625 N/m².

A (the piston area) = 0.0760 m².

Pressure signifies force per unit area, mathematically represented as

P = F/A.

From this, we find F = P × A.

F = 506625 × 0.0760.

Therefore, F = 38503.5N.

Thus, the piston experiences a force of 38503.5N.

6 0
2 months ago
4. Which of the following statements correctly describe atoms? Select all that apply.
castortr0y [3046]

Answer:

A, B, and C

Explanation:

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Atoms consist mostly of void, which excludes them from the other responses.

This confirms that A, B, and C are the right choices.

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1 month ago
49.9 g per day of a certain industrial waste chemical P arrives at a treatment plant settling pond with a volume of 300 m^3. P i
Alekssandra [3086]

Answer:

The concentration of P in the pond at equilibrium is 0.034 g/m³

Explanation:

Given the total mass = 49.9 g

1 day = 24 hours

mass per hour;

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Given the half-life = 3.4 hours

For a first-order reaction; k, the rate constant = ln2/t, where t is the half-time

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Substituting all parameters into the equation k C_{A} V;

Mass lost to sunlight = k C_{A} V  

C_{A} = Incoming mass per hour / kV

= 2.079 g/hr / (0.2038 hr⁻¹ x 300 m³) C_{A}

=  

0.034 g/m³C_{A}

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A skeletal formula is usually used for organic compounds
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