Total energy associated with a spring:
When x = 0.5a:
The ratio:
When x = 0.5a:
The ratio:
A typical human contains 5.00 l of blood, and it takes 1.00 min for all of it to pass through the heart when the person is resti
ng with a pulse rate of 74.0 heartbeats/ minute. on the average, what volume of blood, in (a) liters and (b) cubic centimeters, does the heart pump during each beat?
2 answers:
Blood volume in (a) liters = 0.0675 liters and (b) in cubic centimeters = 67.5 cm³
Additional information
Seven primary quantities have been identified following international guidelines, which include:
1. Length measured in meters (m)
2. Time measured in seconds (s)
3. Mass measured in kilograms (kg)
4. Temperature expressed in kelvin (K)
5. Light intensity measured in candela (cd)
6. Electric current quantified in amperes (A)
7. Amount of substance counted in moles (m)
The length serves to define the distance between two locations
The notation is generally represented as l for length
Volume represents a derived measurement based on the principal length
Volume can be stated in liters, milliliters, or cubic meters
Conversions include:
1 cc = 1 cm³
1 dm = 1 Liter
1 mL = 1 cm³
1 L = 1 dm³
In this case, 5 liters of blood flows through the heart in 1 minute The heart completes 74 beats per minute Thus, our equation is straightforward:5 liters = 1 minute
74 beats = 1 minuteConsequently, during one heartbeat, the blood volume is:
= 5 liters / 74 beats= 0.0675 liters
Upon conversion to cm³:
1 L = 1 dm³ = 10³ cm³0.0675 liters = 0.0675.10³ cm³
= 67.5 cm³
For further details
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What is the total mass in micrograms of cofactor
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Tags: volume, liters, heart, beats, blood
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solution:
the spring force applied by a spring with spring constant k can be expressed as
where k acts as the spring constant
and x indicates the spring's deformation
to determine the work completed by the spring
the amount of work done by the spring when moving from x=0 to x=L
substituting the limits x=0 and x=L
we derive the work done in terms of k and L
Response:
The car's acceleration magnitude is 35.53 m/s²
Details:
Given;
acceleration of the truck, = 12.7 m/s²
mass of the truck, = 2490 kg
mass of the car, = 890 kg
let the acceleration of the car during the collision =
Using Newton's third law of motion;
The force exerted by the truck equals the force exerted by the car.
The car's force acts in the opposite direction.
Thus, the car's acceleration magnitude is 35.53 m/s²