Answer:
I'm uncertain
Explanation:
since I didn't provide a correct answer, continue with my inquiries and you can use 'I'm uncertain' for 100 points.
Answer:
A) The updated amplitude = 0.048 m
B) Period T = 0.6 seconds
Explanation: Please refer to the attached documents for the solution.
Explanation:
- A substance will float if it has a lower density than the liquid it is placed in.
- A substance will sink if its density exceeds that of the liquid.
Density of corn syrup = 
1) Density of gasoline = 
Gasoline's density is less than that of corn syrup, indicating it will float in corn syrup.
2) Density of water = 
Water's density is also less than that of corn syrup, meaning it will float in corn syrup.
3) Density of honey = 
Honey's density exceeds that of corn syrup, so it will sink in corn syrup.
4) Density of titanium = 
The density of titanium is greater than that of corn syrup, hence it will sink in corn syrup.
Esta pregunta está incompleta, la pregunta completa es;
La figura muestra un recipiente sellado en la parte superior por un pistón móvil. Dentro del recipiente hay un gas ideal a 1.00 atm. 20.0°C y 1.00 L.
"¿Cuál será la presión dentro del recipiente si el pistón se mueve hasta la marca de 1.60 L mientras se mantiene constante la temperatura del gas?"
Answer:
la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L manteniendo constante la temperatura del gas
Explicación:
Dado que;
P₁ = 1.00 atm
P₂ =?
V₁ = 1 L
V₂ = 1.60 L
la temperatura del gas se mantiene constante
sabemos que;
P₁V₁ = P₂V₂
por lo que hacemos la sustitución
1 × 1 = P₂ × 1.60
P₂ = 1 / 1.60
P₂ = 0.625 atm
Por lo tanto, la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L mientras la temperatura del gas se mantiene constante