The solar panels used by Mark function because of the photoelectric effect. Light shines on the cells causing electrons to be ej

Answer:

2.87 m

Explanation:

Given parameters:

Mass of the ball (m) = 60 g = 0.06 kg

Height of the tube (h) = 0.70 m

Force applied on the ball by compressed air (F) = 3.0 N

Initial velocity of the ball (u) = 0 m/s (Assumed)

Final velocity of the ball at the tube's exit (v) =?

Acceleration of the ball (a) =?

The ball's weight is derived from multiplying mass and gravity. Therefore,

Weight (W) =

Thus, the total force acting on the ball equals the net of upward force minus the weight.

Net force = Air force - Weight

According to Newton's second law, net force equals the mass multiplied by acceleration.

Acceleration (a) is calculated as 40.2 m/s².

Using the motion equation, we find:

Let’s denote the maximum height achieved as 'H'.

Next, we apply the principle of energy conservation from the pipe's peak to the maximum height.

A decrease in kinetic energy equals an increase in potential energy.

Substituting the values, we solve for 'H', yielding:

Hence, the ball ascends to a height of 2.87 m above the top of the tube.

Refer to the attached file for the solution

Response:

216000 W or 216 kW

Details:

Power: This refers to the rate at which energy is utilized or consumed. The standard unit for power is the Watt (W).

In general,

Power = Energy/time

P = E/t........................ Equation 1.

However,

E = 1/2mv²..................... Equation 2

with m representing mass, and v indicating velocity.

Substituting equation 2 into equation 1,

P = 1/2mv²/t...................... Equation 3

Assuming flow rate (Q) = m/t,

Q = m/t................ Equation 4

Insert equation 4 into equation 3,

P = Qv²/2........................ Equation 5

Where Q stands for flow rate, v is velocity, and P denotes power.

Given: Q = 120 kg/s, v = 60 m/s

Plug these values into equation 5,

P = 120(60)²/2

P = 60(60)²

P = 60×3600

P = 216000 W.

Thus, the potential power generation of the water jet is 216000 W or 216 kW.

Answer and Explanation:

currents i = 2.9 A

           i ' = 4.4 A

The magnitude (in T.m) of the path integral of B.dl around the window frame is calculated as = μo * the enclosed current

          = μo* ( i ' - i )

According to Ampere's law

where μo = permeability of free space = 4π * 10 ^-7 H/m

Substituting the values gives us the magnitude (in T.m) of the path integral of B.dl = (4π*10^-7)(2.9+4.4)

                                 = 1.884 * 10^-6 Tm