When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri

Let's represent molecules with symbols as follows:

                   C₂O₄  =  X
and
                    H₂O  =  Y
Then,
                                K [ Co (X)₂ (Y)₂ ]

Since Potassium (K) has an oxidation number of +1

To achieve neutrality, the oxidation number of the coordination sphere needs to equal -1.
Thus,
                                    [ Co (X)₂ (Y)₂ ]  =  -1
Given that,
           the O.N of X is -2
Therefore,
       O.N of (X)₂ equals -4

Additionally,
O.N of H₂O is zero since it remains neutral. Therefore,

                                    [Co - 4 + 0 ]  =  -1
Or,
                                    Co  =  -1 + 4

                                    Co  =  +3

Conclusion:
          The oxidation number for the coordination sphere is -1, and the oxidation state of copper is +3.

Clarification:

To obtain the specific element, you should multiply the grams provided by the ratio of grams of that particular element within its complete compound.

Since the query did not indicate the amount of NO2 produced, we can consider its mass to be negligible, thus assigning 1 mole to Nitrogen.

Answer:

6

Explanation:

H6 indicates the presence of helium atoms, with 6 representing their quantity.

Answer:

B, D

Explanation:

We need to recognize that the ice will rise in temperature from -6.5 ºC to 0 ºC for it to change into water.

Let's define q₁ as the heat needed to warm the ice to 0ºC, and q₂ as the heat for the transition from solid to liquid.

The calculation for q₁ is as follows:

q₁ = s x m x ΔT, where s represents the specific heat of ice (2.09 J/gºC), m is the mass, and ΔT is the temperature difference.

For q₂, the enthalpy of fusion is computed as:

q₂ = C x ΔT

with C indicating the specific heat for the phase transition, denoted as AH in kJ/mol.

All necessary data for computing q₁, q₂, and the total heat change (q₁ + q₂) is provided.

q₁ = 25.0 g x (2.09 J/gºC) x (0 - (-6.5 ºC))

q₁ = 339.6 J = 0.339 kJ

q₂ = (25 g/18 g/mol) x 6.02 kJ/mol = 1.39 x 6.02 kJ = 8.36 kJ

Combining these values gives us qtotal = 0.339 kJ + 8.36 kJ = 8.70 kJ.

Now we can answer the question:

(a) False, AH refers to the heat capacity during melting.

(b) True, as we concluded earlier.

(c) False, there’s only one phase transition from solid (ice) to liquid.

(d) True based on our calculations above.

(e) False, according to our findings.

The rate equation for a first order reaction can be expressed as follows:

In this context, k represents the reaction's rate constant, t denotes the time the reaction takes, is the initial concentration, and is the concentration at time t.

The rate constant of the reaction is .

(a) If we start with an initial concentration of 100, when 90% of the substance is eliminated, the remaining quantity at time t will be 100-90=10. By substituting the values,

The time required to destroy 90% of the substance amounts to 23.03 days.

(b) If the initial concentration is set at 100, when 99% is destroyed, the present amount at time t will be 100-99=1. By substituting the input values,

This results in a duration of 46.06 days required to eradicate 99% of the chemical.

(c) Should the initial concentration be set at 100, with 99.9% of the chemical removed, the remaining quantity at time t will be 100-99.9=0.1. Substituting the values yields

Thus, the time needed to eliminate 99.9% of the chemical is calculated as 69.09 days.