In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?

Chemistry

1 answer:

lorasvet [2.7K]4 months ago

7 0

The total atom count in the sample is obtained by aggregating the number of atoms from each element in it.

The number of gold atoms, $Au$ , found in $KAu(CN)_2$ , equals $6.66\times 10^{20}$ atoms (according to given data).

Based on the compound formula $KAu(CN)_2$ , it's evident that potassium and gold quantities are equivalent, while carbon and nitrogen quantities are double that amount.

Thus, the number of atoms of each element is as follows:

For potassium, $K$ , in $KAu(CN)_2$ equals $6.66\times 10^{20}$ atoms.

For carbon, $C$ , in $KAu(CN)_2$ equals $2\times6.66\times 10^{20}$ atoms, which totals $13.32\times 10^{20}$ .

For nitrogen, $N$ , in $KAu(CN)_2$ equals $2\times6.66\times 10^{20}$ atoms, which totals $13.32\times 10^{20}$ .

The total atoms in $KAu(CN)_2$ are calculated as: Number of gold, $Au$ + Number of potassium, $K$ + Number of carbon, $C$ + Number of nitrogen, $N$ .

Hence, the overall atom count is $6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}$ .

The total number of atoms amounts to $39.96\times 10^{20}$ atoms.

Consequently, the total atom quantity in $KAu(CN)_2$ is $3.996\times 10^{21}$ atoms.

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