What mass of water in grams will fill a tank 100 cm long, 50 cm wide, and 30 cm high? Knowing that the density of water is 1 g/m

Answer:

When HBCG and BCG^- are at the same concentration, the resulting color is green. This green shade initially becomes visible at a pH of 3.8.

Explanation:

HBCG serves as an indicator formed by dissolving solids in ethanol.

Since

Ka=[BCG−][H3O+][HBCG] When [BCG-] equals [HBCG], it follows that Ka = [H3O+].

<pWith a pH of 3.8,<pKa= [H3O+] = -antilog pH = -antilog (3.8)

Ka= 1.58 ×10^-4

Answer:

Explanation:

In a desert cave, an artifact has been discovered. The anthropologists investigating this artifact want to determine its age. They note that the current activity level of the artifact is 9.25 decays/s, and the carbon mass present is 0.100 kg. To ascertain the artifact's age, they will employ specific constants:

r=1.2

The formula for carbon 14 activity is

where,

is the initial activity of the substance

Now, solve for t

since,

Thus, the age of the artifact is

to two significant figures = 6300 years

Response:

9.9 ml of 0.200M NH₄OH(aq)

Reasoning:

3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)

What volume in ml of 0.200M NH₄OH(aq) will fully react with 12ml of 0.550M FeCl₃(aq)?

1 x Molarity of NH₄OH x Volume of NH₄OH Solution(L) = 2 x Molarity of FeCl₃ x Volume of FeCl₃ Solution

1(0.200M)(Volume of NH₄OH Soln) = 3(0.550M)(0.012L)

=> Volume of NH₄OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liters = 9.9 milliliters

Convert 55.0g Ca(OH)2 to moles.

The calculation shows that 55.0g of Ca(OH)2 corresponds to 0.742 moles.

To find the volume, divide 0.742 mol of Ca(OH)2 by its molarity of 0.680M, yielding approximately 1.09L of Ca(OH)2.

If you disregard the negligible volume of the Ca(OH)2 itself, the resulting total volume of a 0.680M solution created by dissolving 55.0g of Ca(OH)2 in an appropriate amount of water would be 1.09L.

The enthalpy change associated with the precipitation reaction is 84 kJ/mole

Why?

The chemical equation for the reaction can be written as

AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)

To determine the enthalpy change, the following equation applies

To calculate the heat (Q):

Next, we need to calculate the number of moles involved in the reaction (n):

With these two values, we can substitute them into the first equation:

Have a great day!