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1 month ago

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Sebuah benda dijatuhkan bebas dari ketinggian 200 m jika grafitasi setempat 10 m/s maka hitunglah kecepatan dan ketinggian benda

saat ek=4ep

1 answer:

inna [3.1K]1 month ago

7 0

Kindly use English in your post so that I or someone else can assist you.

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A composite wall separates combustion gases at 2400°C from a liquid coolant at 100°C, with gas and liquid-side convection coeffi

Ostrovityanka [3204]

Response:

$\text{heat loss} = 24864.05 \ W/m^2$

Clarification:

If

$T_1$ , $T_2$ represent the temperatures of gases and liquids in Kelvins,

$t_1$ and $t_2$ denote the thicknesses of the gas layer and steel slab in meters,
$h_1$ , $h_2$ are the convection coefficients for gas and liquid in $W/m^2 \cdot K$ ,
$R_c$ represents the contact resistance in $m^2 \cdot K/W$ ,

and $k_1, k_2$ signify thermal conductivities of gas and steel in $W/m \cdot K$ ,

then: part(a):

$\text{heat loss } = \frac{T_1 - T_2} { \frac{1}{h_1} + \frac{t_1}{t_2} + R_c + \frac{t_2}{k_2} + \frac{1}{h_2}}$

by employing known values:

$\text {heat loss} = 2486.05 W/m^2$

part(b): Utilizing the rate equation:

$\text {heat loss} = h_1 (T_1 - T_{s1})$

the surface temperature is $T_{s1} = 1678.438 \ K$

and $T_{c1} = T_{s1} - \frac {t_1 (\text{heat loss})}{k_1} = 1664.560 \ K$

Correspondingly

$T_{c2} = T_{c1} - R_c (\text{heat loss}) = 421.357 \ K$

$T_{s2} = T_{c2} - \frac {t_2 (\text{heat loss})}{ k_2} = 397.864 \ K$

The temperature profile is depicted in the image provided

3 0

2 months ago

A 100-watt light bulb radiates energy at a rate of 100 J/s. (The watt, a unit of power or energy over time, is defined as 1 J/s.

Keith_Richards [3271]

Answer:

$2.64\times 10^{20}$ The number of photons emitted each second is

Explanation:

Let 'n' stand for the quantity of photons released by the bulb.

Provided Information:

The bulb radiates energy at a rate of 100 J per second (E).

Wavelength of emitted light is (λ) = 525 nm = $525\times 10^{-9}\ m$

The energy of a photon is calculated by:

Where,

$E_0=\frac{hc}{\lambda}$

Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,

$h\to Planck's\ constant=6.626\times 10^{-34}\ Js\\\\c\to Speed\ of \ light=3\times 10^{8}\ m/s$

To express in terms of 'n', we find:

$E=nE_0\\\\E=\frac{nhc}{\lambda}$

Insert the provided values and solve for 'n'. The resulting calculation yields

$n=\frac{E\lambda}{hc}$

Consequently,

photons are discharged every second. $n=\frac{100\times 525\times 10^{-9}}{6.626\times 10^{-34}\times 3\times 10^{8}}\\\\n=2.64\times 10^{20}$

$2.64\times 10^{20}$

8 0

1 month ago

If you have an effusive personality, then it __________ of you. motor oil will __________ across the gravel if it spills out of

Keith_Richards [3271]

The first word in the blank is "pours out of you," while the second word to fill in is "diffuse." This implies that a person with an effusive nature tends to openly express their feelings, just as spilled motor oil will spread out over gravel.

6 0

2 months ago

A spacecraft is traveling with a velocity of +3250 m/s. Suddenly the retrorockets are fired, and the spacecraft begins to slow d

Yuliya22 [3333]

Answer:3249.33 m/s

Explanation:

Provided:

Initial velocity = 3250 m/s

Acceleration $=-10 m/s^2$

Displacement = 215 km

Applying the equation of motion:

$v^2-u^2=2as$

where:

v = the final velocity

u = the initial velocity

a = acceleration

s = displacement

$v^2-3250^2=2\times (-10)\times 215$

$v^2=3250-4300$

v = 3249.33 m/s

4 0

2 months ago

When jumping, a flea accelerates at an astounding 1000 m/s2 but over the very short distance of 0.50 mm. If a flea jumps straigh

Yuliya22 [3333]

Answer:

A flea can attain a maximum elevation of 51 mm.

Explanation:

Hello!

The following equations describe the height and velocity of the flea:

During the jump:

h = h0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

In free fall:

h = h0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

h = flea's height at time t.

h0 = initial height.

v0 = starting velocity.

t = time interval.

a = flea's acceleration while jumping.

v = flea's velocity at that specific time.

g = gravitational acceleration.

Initially, we need to determine the time taken for the flea to attain a height of 0.0005 m. This will help us calculate the flea's velocity during the jump:

h = h0 + v0 · t + 1/2 · a · t²

If we assume the ground as the origin, thus h0 = 0. Since the flea starts stationary, v0 = 0. Therefore:

h = 1/2 · a · t²

We need to find the value of t when h = 0.0005 m:

0.0005 m = 1/2 · 1000 m/s² · t²

0.0005 m / 500 m/s² = t²

t = 0.001 s

Next, we calculate the velocity achieved during that time:

v = v0 + a · t (v0 = 0)

v = a · t

v = 1000 m/s² · 0.001 s

v = 1.00 m/s

At a height of 0.50 mm, the flea's velocity stands at 1.00 m/s. This initial speed will reduce due to gravity's downward pull. When the speed reaches zero, the flea will have reached its peak height. Using the velocity equation, let's determine the time taken to reach maximum height (v = 0):

v = v0 + g · t

At peak height, v = 0:

0 m/s = 1.00 m/s - 9.81 m/s² · t

-1.00 m/s / -9.81 m/s² = t

t = 0.102 s

Now, we can compute the height attained by the flea during this time:

h = h0 + v0 · t + 1/2 · g · t²

h = 0.0005 m + 1.00 m/s · 0.102 s - 1/2 · 9.81 m/s² · (0.102 s)²

h = 0.051 m

A flea reaches a maximum height of 51 mm.

5 0

2 months ago