In a water molecule, the sharing of electrons occurs between the oxygen and hydrogen atoms within covalent bonds; however, this sharing is unequal. The oxygen atom holds a stronger pull on the electrons compared to the hydrogen atoms in the bond.
To find the answer, start by calculating the total mass of the copper utilized:
Copper used = 100 pennies x 3.0g Cu per penny = 300.0 g Cu
Next, identify the path and molar ratios from Cu produced back to CuFeS2 needed using the established balanced reactions:
1 Cu2S from 2 CuS; 2Cu from 1 Cu2S; 2CuS from 2CuFeS2
Thus, 2Cu comes from 2CuFeS2, indicating a 1:1 molar ratio.
Then convert grams of Cu to moles and grams of CuFeS2:
= 300.0 g Cu * 1 mol Cu/63.546g Cu * 2 mol CuFeS2/2 moles Cu
= 4.72 moles CuFeS2
The required amount of chalcopyrite mined = 4.72 moles CuFeS2 * 183.54 g CuFeS2/1 mole
CuFeS2 = 866.49 g CuFeS2
mass of sulfur = 96 g no of moles of sulfur dioxide in
molecules =
= 2 moles therefore mass of sulfur dioxide = moles × atomic number = 2 × (16 + 32) = 96
