answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dennis_Churaev
4 days ago
9

In a demonstration, a 4.00 cm2 square coil with 10 000 turns enters a larger square region with a uniform 1.50 T magnetic field

at a speed of 100 m/s. The plane of the coil is perpendicular to the field lines. If the breakdown voltage of air is 4 000 V/cm on that day, the largest gap you can have between the two wires connected to the ends of the coil and still get a spark is:
Physics
1 answer:
serg [3.2K]4 days ago
6 0

Explanation:

It is stated that,

Area of square coil, A=4\ cm^2=0.0004\ m^2

Length of one side of the square, L = 0.02 m

Number of coils, N = 10000

Consistent magnetic field, B = 1.5 T

Velocity, v = 100 m/s

An electromotive force is produced in the coil calculated as:

E=NBLv

E=10000\times 1.5\times 0.02\times 100

E = 30000 V

Breakdown voltage of air, V=4000\ V/cm=400000\ V/m

Let d be the distance between the ends of the coil wires that can still produce a spark. Therefore,

Electric field, E'=\dfrac{V}{d}

\dfrac{30000}{d}=400000

d = 0.075 m

Thus, this forms the final answer.

You might be interested in
A rotating beacon is located 2 miles out in the water. Let A be the point on the shore that is closest to the beacon. As the bea
serg [3228]

Answer:

v = 3369.2 m/s

Explanation:

The beacon is rotating at an angular speed of

f = 10 rev/min

so we have

\omega = 2\pi f

\omega = 2\pi(\frac{10}{60})

\omega = 1.047 rad/s

We know that

v = r \omega

At this point we have

r = 2 miles = 2(1609 m)

r = 3218 m

So we can conclude with

v = 3218(1.047)

v = 3369.2 m/s

6 0
1 month ago
In broad daylight, the size of your pupil is typically 3 mm. In dark situations, it expands to about 7 mm. How much more light c
Sav [2826]

Answer:

31.4 mm²

Explanation:

The ability of a telescope or eye to gather light can be expressed by the formula,

GDP=\pi } \frac{d^{2} }{4}

where d signifies the diameter of the pupil.

In bright daylight, the usual size of the pupil is 3 mm.

GDP_{b} =\pi \frac{3^{2} }{4}

Conversely, in darkness, the diameter typically enlarges to 7 mm.

GDP_{b} =\pi \frac{7^{2} }{4}

This indicates an increase in light-gathering capacity.

Increase=\pi \frac{49}{4} -\pi \frac{9}{4} \\Increase=31.4 mm^{2}

Thus, the amount of light the eye can capture is 31.4 mm².

3 0
28 days ago
An electric buzzer is activated, then sealed inside a glass chamber. When all of the air is pumped out of the chamber, how is th
ValentinkaMS [3084]
The intensity of the sound increases because sound waves are mechanical waves, meaning they cannot move through a vacuum and require a medium to propagate.
4 0
15 days ago
A book that weighs 0.35 kilograms is kept on a shelf that’s 2.0 meters above the ground. A picture frame that weighs 0.5 kilogra
Softa [2661]
Upon calculating, I'm nearly certain that the answer is "...to a height of 1.4 meters." Happy to assist!:)
4 0
19 days ago
Read 2 more answers
While dangling a hairdryer by its cord, you observe that the cord is vertical when the hairdryer isoff and, once it is turned on
Yuliya22 [2962]

Answer:

The air exiting from the hairdryer is moving at a speed of 10 m/s.

Explanation:

The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram

(1).\: tan (5^o) = \dfrac{F_t}{Mg}

by substituting M =0.420kg, g = 9.8m/s^2 into the equation and resolving for F_t we find:

F_t = Mg\:tan(5^o)

F_t = (0.420kg)(9.8m/s^2)\:tan(5^o)

\boxed{F_t = 0.3601N.}

This thrust is linked to the speed of air ejection v through the equation

(2).\: F_t = v\dfrac{dM}{dt}

where dM/dt signifies the rate of air ejection, which is known to be

0.06m^3/2s  = 0.03m^3/s

and since 1m^3 = 1.2kg,

0.03m^3/s \rightarrow 0.036kg/s

\dfrac{dM}{dt}  = 0.036kg/s,

by inserting these values into equation (2), we obtain the value of F_t as:

0.3601N = 0.036v

resulting in

v= \dfrac{0.3601}{0.036}

\boxed{v =10m/s.}

which indicates the air velocity discharged from the hairdryer.

6 0
1 month ago
Other questions:
  • A large crate with mass m rests on a horizontal floor. The static and kinetic coefficients of friction between the crate and the
    5·2 answers
  • A 2.50-kg textbook is forced against a horizontal spring of negligible mass and force constant 250 N/m, compressing the spring a
    10·1 answer
  • A 0.050-kg lump of clay moving horizontally at 12 m/s strikes and sticks to a stationary 0.15-kg cart that can move on a frictio
    15·1 answer
  • Imagine you are riding on a yacht in the ocean and traveling at 20 mph. You then hit a golf ball at 100 mph from the deck of the
    6·2 answers
  • Which process is a form of mechanical weathering?
    15·2 answers
  • You're riding a unicorn at 25 m/s and come to a uniform stop at a red light 20m away. What's your acceleration?
    5·2 answers
  • An ant travels 2.78 cm [W] and then turns and travels 6.25 cm [S 40 degrees E]. What is the ant's total displacement?
    14·1 answer
  • A floating balloon can be formed when the substance helium is released from a compressed container into a flat rubber balloon. T
    9·2 answers
  • In pottery class, you throw a pot from a lump of wet clay. your pot's mass is 5.5 kg. after the pot is fired, it's mass is 4.9 k
    15·1 answer
  • After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!