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Stells
3 months ago
7

What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a

nd the ground is 0.76.

Physics
1 answer:
serg [3.5K]3 months ago
8 0

Response:

T = 38.38 N

Explanation:

In this case

mass of can = m = 3 kg

g= 9.8 m/sec²

angle θ = 40°

As illustrated, we observe the vertical and horizontal components of the tension force T.

If the can is on the verge of slipping, then the horizontal component of the tension force should equal the frictional force.

First, we calculate the frictional force

Fs = μ R

where

μ = 0.76

R = weight of the can = mg = 3 × 9.8 = 29.4 N

Now, regarding the horizontal component of tension, we have

Tx = T cos 40° = T × 0.7660 N

which leads to T × 0.7660 = 29.4

Thus, T = 38.38 N

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While dangling a hairdryer by its cord, you observe that the cord is vertical when the hairdryer isoff and, once it is turned on
Yuliya22 [3333]

Answer:

The air exiting from the hairdryer is moving at a speed of 10 m/s.

Explanation:

The thrust generated by the hairdryer enables it to maintain an elevation angled at 5° from vertical; thus, we derive from the force diagram

(1).\: tan (5^o) = \dfrac{F_t}{Mg}

by substituting M =0.420kg, g = 9.8m/s^2 into the equation and resolving for F_t we find:

F_t = Mg\:tan(5^o)

F_t = (0.420kg)(9.8m/s^2)\:tan(5^o)

\boxed{F_t = 0.3601N.}

This thrust is linked to the speed of air ejection v through the equation

(2).\: F_t = v\dfrac{dM}{dt}

where dM/dt signifies the rate of air ejection, which is known to be

0.06m^3/2s  = 0.03m^3/s

and since 1m^3 = 1.2kg,

0.03m^3/s \rightarrow 0.036kg/s

\dfrac{dM}{dt}  = 0.036kg/s,

by inserting these values into equation (2), we obtain the value of F_t as:

0.3601N = 0.036v

resulting in

v= \dfrac{0.3601}{0.036}

\boxed{v =10m/s.}

which indicates the air velocity discharged from the hairdryer.

6 0
3 months ago
Explain whether or not there is any difference between a light ray emitted by a candle flame and one reflected off the cover of
inna [3103]
The distinction lies in the fact that the candle emits an emission spectrum, while the book reflects an absorption spectrum. In the case of the book, light is observed from all directions, causing its reflection to be diffuse. Explanation: The light emitted by a candle originates from the heat of the flame, composed of a combination of emissions from a black body at that temperature along with emissions from the chemical elements within the candle. On the contrary, the light reflected off a book cover consists of the incident light spectrum minus the wavelengths that trigger electronic transitions in the cover's elements, resulting in dark areas on the spectrum. Consequently, the difference stems from the candle producing an emission spectrum, whereas the book showcases an absorption spectrum. For a book's cover to reflect light specularly, incident rays would need to reflect uniformly, creating dark areas. However, since light is observed from all directions when reflecting off a book, the result is diffuse reflection.
6 0
2 months ago
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