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Ymorist
7 days ago
9

To a cyclist riding due west with a speed of 4 m/s a wind appears to

Physics
1 answer:
Sav [3K]7 days ago
7 0

Answer:

The actual wind speed coming from south to west is V = 3.08 m/s

Explanation:

Given information,

The cyclist is moving towards west at v = 4 m/s

The wind seems to come from the south, U = 2 m/s

Let Ф designate the angle formed between the wind's direction and the west axis,

Consequently, the actual wind speed is given by:

                                 V = (v - U) sec Ф

                                     = 2 sec Ф

Assuming Ф = 30°, (The student may provide the necessary Ф value)

                                  V =  2(1.54)

                                   V = 3.08 m/s

Thus, the actual wind velocity blowing from south to west is V = 3.08 m/s

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Answer:

Speeds of 1.83 m/s and 6.83 m/s

Explanation:

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5m=m(v_1 +v_2)

Thus, v_1+v_2=5

After the collision, the kinetic energy doubles, therefore:

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2v_o^{2}=v_1^{2} + v_2^{2}

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2*(5^{2})= v_1^{2} + v_2^{2}We know that v_1+v_2=5 leads to v_1=5-v_2

50=(5-v_2)^{2}+ v_2^{2}

50=25+v_2^{2}-10v_2+v_2^{2}

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Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25. v_2=6.83 m/s

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Response:

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