The rod measures 450mm in length, while the disk has a radius of 75mm. An upward-supporting pin holds the assembly in place when Θ=0, and there exists a torsional spring with a constant of k=20N m/rad at the pin. One end of the rod connects to the pin, while the other connects to the disk.
<span> </span><span>When the net torque and moment of inertia are given, calculating becomes straightforward.
Using the equation torque = I * alpha, where I represents the moment of inertia and alpha is the angular acceleration.
Consequently, 0.098 / 0.000075 results in 1306.666... rad / s^2
While the angular acceleration stays the same, you can also determine the angular velocity at that instance, which is 21.36 rad / s.</span>
Given that,
Force F= 30,000 N
mass m= 4000 kg
acceleration =?
as F= ma
a= F/m
a= 30,000/4000
a= 7.5 m/s²
The acceleration of the aeroplane will, therefore, be 7.5 m/s².
