Compound A reacts with Compound B to form only one product, Compound C, and it's known the usual percent yield of C in this reac

The isotopic mass of 47Z is calculated to be 46.96 amu. Isotopes of a single element differ in neutron count, and to ascertain the relative atomic mass, we consider each isotope's mass weighted by their natural abundance. This provided a computation to derive the mass of 47Z.

The partial pressure of nitrogen gas is calculated to be 21.16 MPa. The partial pressure of oxygen equates to 5.62 MPa, and the overall gas pressure is stated as 26.78 MPa. This adheres to the principle that the total pressure in a gas system equals the sum of all individual gas partial pressures. Thus, the total pressure in the system reflects the sum of the partial pressures of nitrogen and oxygen. Accordingly, the partial pressure for nitrogen can be derived as follows: Total pressure minus the partial pressure of oxygen. Thus resulting in: 26.78 - 5.62, which gives a partial pressure of nitrogen at 21.16 MPa.

Response:

0.8853 mL

Clarification:

Initially, we convert 13 lb to kg, remembering that 1 lb = 0.454 kg:

• 13 lb * = 5.902 kg

Next, we determine the required mg of acetaminophen to administer, applying the recommended dosage and infant's weight:

• 15 mg/kg * 5.902 kg = 88.53 mg

Finally, we compute the necessary mL of suspension, utilizing its concentration:

• 88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mL

(c) Cu + S → CuS is classified as a redox reaction

Explanation:

The following reactions are presented:

(a) K₂CrO₄ + BaCl₂ → BaCrO₄ + 2 KCl

(b) Pb²⁺ + 2 Br⁻ → PbBr₂

(c) Cu + S → CuS

Reaction (c) represents a redox reaction, as the oxidation states of the elements are changing. In this case:

Cu + S → CuS

In its elemental form, Cu has an oxidation state of 0, while in CuS (copper sulfide), its oxidation state changes to +2.

Similarly, S in its elemental form has an oxidation state of 0 and is -2 in CuS (copper sulfide).

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redox reactions

Answer:

The integer value of x in the hydrate is 10.

Explanation:

Molar concentration of the solution = 0.0366 M

Volume of the solution = 5.00 L

Moles of hydrated sodium carbonate = n

Weight of hydrated sodium carbonate = n = 52.2 g

Molar mass of hydrated sodium carbonate = 106 g/mol + x * 18 g/mol

By solving for x, we arrive at:

x = 9.95, approximating to 10

The integer x in the hydrate equals 10.