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poizon
3 months ago
9

The graph above shows the changes in temperature recorded for the 2.00 l of h2o surrounding a constant-volume container in which

a 1.00 g sample of benzoic acid was combusted. Assume that heat was not absorbed by the container or lost to the surroundings

Chemistry
1 answer:
Alekssandra [3K]3 months ago
6 0

Answer:

25.2 kJ

Explanation:

The full question can be found in the image linked to this response.

It's important to highlight that the heat absorbed by the 2.00 L of water for increasing its temperature from the beginning to the end comes solely from the burning of benzoic acid, as there are no heat transfers to the container or the surroundings.

To find the heat released from benzoic acid combustion, we simply measure the heat needed to warm the water.

Q = mCΔT

To find the mass of the water,

Density = (mass)/(volume)

Mass = Density × volume

Density = 1 g/mL

Volume = 2.00 L = 2000 mL

Mass = 1 × 2000 = 2000 g

C = specific heat of water = 4.2 J/g.°C

ΔT = (final temperature) - (Initial temperature)

<pAccording to the graph,

Final water temperature = 25°C

Initial water temperature = 22°C

ΔT = 25 - 22 = 3°C

Q = (2000×4.2×3) = 25,200 J = 25.2 kJ

Hope this Helps!!!

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4 months ago
Read 2 more answers
Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
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1) The chemical equation is

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) Molar ratios are as follows:

1 mol Cu: 2 moles AgNO3: 1 mol Cu (NO3)2: 2 mol Ag

3) Converting 12.83 * 10^23 atoms of Cu to moles gives:

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Answer: 459.9 g
5 0
3 months ago
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