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lutik1710
1 month ago
15

Determine the number of atoms in 1.85 ml of mercury. (the density of mercury is 13.5 g/ml.)

Chemistry
1 answer:
lions [2.9K]1 month ago
7 0
To begin with, we need to calculate the mass of the mercury:
Pressure = mass/volume
mass = pressure x volume = 13.5 x 1.85 = 24.975 gm

Next, we find the moles in 24.975 gm:
From the periodic table, mercury's molar mass is 200.59
mass = number of moles x molar mass
number of moles = 24.975 / 200.59 = 0.1245 mole

Finally, to find the number of atoms:
Each mole consists of 6.02 x 10^23 atoms
number of atoms = 0.1245 x 6.02 x 10^23 = 7.4949 x 10^22 atoms
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in a typical person, the level of glucose is about 85 mg/ 100 mL of blood. if an average body contains about 11 pt of blood, how
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It's important to remember that 1 pint equals 473.1765 mL, therefore 11 pints amounts to 5204.9415 mL.

We can formulate a proportion based on the problem statement

(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose

5 0
1 month ago
Cathodic protection of a metal pipe against corrosion usually entails __________.
VMariaS [2998]

Answer:

C. connecting an active metal to designate the pipe as the cathode in an electrochemical cell.

Explanation:

Cathodic protection involves a method to manage the accelerated corrosion of a metal surface by designating it as the cathode within an electrochemical cell. This is accomplished by attaching the protected metal to a more sacrificial metal, which acts as the anode.

This method helps to preserve the metal by introducing a highly reactive metal that serves as the anode, supplying free electrons. By adding these free electrons, the active metal gives up its ions, protecting the less reactive steel from corrosion.

3 0
2 months ago
Equimolar samples of CH3OH(l) and C2H5OH(l) are placed in separate, previously evacuated, rigid 2.0 L vessels. Each vessel is at
Alekssandra [3086]

Answer:

Complete Question:  

Equimolar quantities of CH3OH(l) and C2H5OH(l) are placed in separate 2.0 L containers that have been evacuated beforehand. Pressure gauges are attached to each container, and the temperature is maintained at 300 K. In both containers, liquid is consistently visible at the bottom. The varying pressure within the vessel that contains CH3OH(l) is illustrated below.

In comparison to the equilibrium vapor pressure of CH3OH(l) at 300 K, the equilibrium vapor pressure of C2H5OH(l) at 300 K is

ANSWER : lower, since the London dispersion forces among C2H5OH molecules surpass those among CH3OH molecules.

Explanation:

To clarify the answer provided, let’s begin by defining some concepts.

The London dispersion force is the least strong type of intermolecular force. It is a temporary force that arises when the electron arrangement in two neighboring atoms creates transient dipoles.  

The vapor pressure of a liquid reflects the equilibrium pressure of its vapor above the liquid (or solid); specifically, it represents the pressure associated with the evaporation of a liquid (or solid) in a sealed environment above the substance.

The pressure will be lower due to the stronger London dispersion forces acting between C2H5OH molecules compared to those between CH3OH molecules. This implies that when intermolecular forces are stronger, they intensify the interactions binding the substance together, thereby reducing the liquid's vapor pressure at any given temperature and making it more difficult to vaporize the substance.

Note: The London dispersion force for C2H5OH is more substantial than for CH3OH because C2H5OH has more electrons than CH3OH.

3 0
3 months ago
In a chemical reaction, 300 grams of reactant A are combined with 100 grams of reactant B. Both A and
KiRa [2933]
I expect the product's mass to be 400 grams. This belief stems from the law of conservation of mass, which states that mass can neither be created nor destroyed. In a sealed system, the mass of the reactants equals the mass of the products. Therefore, since the total mass of the reactants is 400 grams, the resulting mass of the products must also be 400 grams

OR

200

8 0
1 month ago
For each reaction, identify the element that gets reduced and the element that gets oxidized. 2AgCl+Zn⟶2Ag+ZnCl2 Identify the el
KiRa [2933]

Answer:

Explanation:

The oxidation state corresponds to the charge of each atomic ion. An increase indicates oxidation of the element while a decrease reflects reduction of the element.

2AgCl+Zn⟶2Ag+ZnCl2

Zinc undergoes oxidation, while Ag experiences reduction.

Ag⁺ changes to Ag (oxidation state decreases), thus Ag is reduced.

Zn alters to Zn⁺² (oxidation state increases), hence Zn is oxidized.

4NH₃+3O₂⟶2N₂+6H₂O

The oxidation state of nitrogen in ammonia is -3

whereas it is zero in elemental nitrogen.

An increase in the oxidation state indicates nitrogen is oxidized.

The oxidation state of oxygen is zero when in molecular oxygen and -2 when in water. Therefore, the oxidation state decreases, indicating oxidation is reduced.

Fe₂O₃+2Al⟶Al₂O₃+2Fe

The oxidation state of Fe in Fe₂O₃ is +3, switching to zero in Fe, so iron is reduced.

Aluminum's oxidation state is zero in Al, rising to +3 in Al₂O₃, indicating it is oxidized.

7 0
2 months ago
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