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VladimirAG
25 days ago
9

Which of the following is most likely to form multiple (double or triple) bonds? 1. Li 2. Cl 3. N 4. H 5. F

Chemistry
1 answer:
lions [2.6K]25 days ago
3 0

Answer: The correct choice is (3).

Explanation:

The atomic number for lithium is 3, and its electron configuration is 2, 1. To achieve stability, it will lose one electron, thus forming a single bond.

Chlorine has an atomic number of 17, with 7 electrons in its outer shell. It will gain an electron to reach stability, resulting in the formation of a single bond.

Nitrogen, with an atomic number of 7 and an electron distribution of 2, 5, must acquire 3 electrons to stabilize. Therefore, nitrogen can form both triple and double bonds.

Hydrogen's atomic number is 1, and it stabilizes by gaining one electron, always forming a single bond.

Fluorine has an atomic number of 9 with 2, 7 electron distribution. It needs to gain one more electron to complete its octet, so it also forms a single bond.

Thus, we conclude that among the listed options, nitrogen is most capable of forming multiple (double or triple) bonds.

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0.22 M
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Solving applied density problems Mr. Auric Goldfinger, criminal mastermind, intends to smuggle several tons of gold across Inter
KiRa [2711]

Answer:

thickness is 0.29 cm

Explanation:

To create a fake iron ball out of gold, we must ensure that its mass matches that of the iron ball. Therefore, we first find the volume of the iron ball using the provided diameter, applying the formula of 4/3 pi r^3.

Given the diameter d = 6 cm; thus, the radius r = 3 cm (d/2).

We calculate the volume of the iron ball: 4/3 * 3.14 * 3^3 = 113.04 cm^3.

The corresponding mass of the iron ball is the volume multiplied by its density: 113.04 * 5.15 g/cm^3 = 582.156 g.

This value represents the mass for the gold ball; now we determine the volume of the gold ball using its density.

Volume of gold ball = mass of gold ball/density of gold = 582.156 g/19.3 g/cm^3 = 30.1635 cm^3.

So this volume must correspond to a hollow sphere with an outer radius R = 3 cm and an unknown inner radius r.

Volume of the hollow ball can be represented as: 4/3 pi [R^3 - r^3].

Thus, 30.1635 cm^3 = 4/3 pi [3^3 - r^3].

30.1635 * 3/(4 * 3.14) = 27 - r^3.

Simplifying gives 7.2046 = 27 - r^3, resulting in r^3 = 19.7954.

Therefore, r = 2.7051 cm.

This indicates the thickness is the outer radius minus the inner radius: 3 - 2.7051 = 0.2949 cm.

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the thickness = 0.29 cm.

8 0
1 month ago
How many micrograms of iron were in the 8.0 mL sample of Greg's blood?
castortr0y [2743]
The result is: 3.36 micrograms of iron in<span> Greg's blood sample.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
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27 days ago
At -70 ∘c and 5.2 atm, carbon dioxide is in which phase?
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6 0
1 month ago
Read 2 more answers
The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that
eduard [2520]

Answer:

The ratios arranged in ascending order are; The ratio of the mass of Y to X in XY2 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY3 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY4 divided by the mass of Y to X in XY

1) Mass ratio = 3

2) Mass ratio = 2

3) Mass ratio = 4

Explanation:

Comprehensive calculations are displayed in the attachment.

3 0
11 days ago
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