1. Independent variable: the variable that can be modified and regulated.
the nail polish on Sarah's nails
2. Dependent variable: outcomes that result from the changes in the independent variable.
the duration of the nail polish's longevity
3. <span> Hypothesis: Different brands of nail polish have varied durations before they chip.
</span> 4. Control group: the <span> independent variable remains unchanged in this setup, not subject to variations.
</span> the schedule of when Sarah applies her nail polish (Sarah colors her nails every Sunday for a month)
the specific base coat and top coat (she <span> applies the same bottom coat and top coat with every kind of nail polish)
weekly habits (she ensures the same routine each week so her nails are not treated more harshly on some weeks).
</span> Experimental group: <span> the independent variable is altered for this group
type of nail polish (Essie, OPI, and Sally Hansen)
</span> 6. Constants: the experimenter (Sally), duration of study (one week), her weekly routine, <span> base coat and top coat, </span>
Answer:
The molar mass of the metal in grams per mole is calculated to be 8.87.
Explanation:
Initially, we can consider a sample of the compound weighing 100 g. This results in:
- 52.92% metal: 52.92 g M
- 47.80% oxygen: 47.80 g O
By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:
moles of oxygen=2.9875
The formula for the metal oxide indicates that:
2 M⁺³ + 3 O²⁻ ⇒ M₂O₃
From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:
Given 52.92 g of metal in the sample, the molar mass of the metal is:
molar mass≅ 8.87 g/mol
The molar mass of the metal in grams per mole is 8.87.
The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.
The force can be determined using the equation F (force) = mass * acceleration. The unit of measurement, N (Newton), is equivalent to kilogram-meter/seconds2.
Thus, F= 1300 kg * 1.07 m/s2 = 1391 N.
The resultant value is 1391 N.
Answer:
The density comes out to be 
Mg/µL
Explanation:
Given data:
The density of nuclear matter is approximately 
kg/m³
1 ml corresponds to 1 cm³
To determine:
The density of nuclear matter in Mg/µL
Solution:
We recognize that:
1 Mg equals 1000 kg
Thus, 1 m³ is equal to cm³
Moreover, 1 cm³ is equivalent to 1 mL
Thus, we can conclude that 1 mL is equal to 10³ µL
With this, we convert the density as follows:
Density = kg/m³
Density = kg/m³ × 
Mg/µL
Density = Mg/µL
The terminal velocity of the object is 12.58 m/s.
Explanation: Terminal velocity occurs when the drag force equals the weight of the object. The gravitational force is calculated as mg = 80 * 9.8 = 784 N. The drag force can then be equated to solve for the terminal velocity, resulting in v = 12.58 m/s or v = -15.58 m/s (which is unfeasible). Thus, the terminal velocity of the falling object is 12.58 m/s.
