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Dmitrij
2 months ago
8

Freon-11, CCl3F has been commonly used in air conditioners. It has a molar mass of 137.35 g/mol and its enthalpy of vaporization

is 24.8 kJ/mol at its normal boiling point of 24C. Ideally how much energy in the form of heat is removed from a room by an air conditioner that evaporates 1.00 kg of freon-11?
Chemistry
1 answer:
alisha [2.9K]2 months ago
0 0

Answer:

180.56 kilojoules of heat energy is extracted when 1.00 kg of freon-11 evaporates.

Explanation:

The molar mass of freon-11 is 137.35 g/mol

The enthalpy of vaporization for freon-11 is 24.8 kJ/mol at its normal boiling point of 24°C. Given that,\Delta H_{vap}=24.8 kJ/mol

Mass of freon-11 evaporated = 1.00 kg = 1000 g

Moles of freon-11 evaporated can be calculated as

\frac{1000 g}{137.35 g/mol}=7.2807 mol

The energy removed in the form of heat when 1.00 kg of freon-11 vaporizes is:

7.28067 mol\times \Delta H_{vap}=7.2807 mol\times 24.8 kJ/mol

=180.56 kJ

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