When air is forced into the open pipe,
L = 
where n represents any whole number such as 1,2,3,4, etc., and λ denotes the wavelength of the oscillation
This implies λ=
It is important to note that n=1 corresponds to the fundamental frequency, n=2 corresponds to the first harmonic, and so forth.
Thus, the third harmonic will be for n=4
With L=6m and n=4, solving for λ yields:
λ=
=3m
The connection between frequency (f), sound speed (c), and wavelength (λ) is given by:
c=f.λ or f= 
Therefore, f=

≈115 Hz
None of the provided options is correct. After contact, A becomes -4 µC, B remains 0 µC, and C ends with +4.0 µC. When spheres A and B touch, charges will redistribute to establish balance, resulting in A = -4 µC, B = -4 µC, C = +4.0 µC. After C and B are touched, both positive and negative charges neutralize each other, leaving A at -4 µC, B at 0 µC, and C at 0 µC.
B. The charge on A is -q; B has no charge. Given that a positive charge is situated at the center of an uncharged metallic sphere which is insulated and disconnected from the ground, a negative charge (-q) will appear on the inner surface A of the sphere. Should the exterior surface B be grounded, it will become neutral, resulting in no charge remaining on surface B.
(B) (length)/(time³) Explanation: The term x = ½ at² + bt³ should meet dimensional consistency. This means that both bt³ and ½ at² must share the same units, which are length. To find the dimension of b, we rearrange the equation: [x] = [b]*[t]³ leads to length = [b]*time³, hence [b] = length/time³.
Answer:
h = 12.8 cm
Explanation:
The initial parameters are as follows:
distance = 6.4 cm
- when the object descends, its weight matches the spring's force
weight = spring force
mg = ky... equation 1
- potential energy stored in a stretched spring = work done by the spring
mgh = 0.5 x k x h^{2}....equation 2
- Substituting from equation 1 into equation 2
kyh = 0.5 x k x h^{2}
y = 0.5 x h
2y = h
- where y is 6.4, yielding the maximum elongation as
h = 2 x 6.4 = 12.8 cm