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Brilliant_brown
6 days ago
5

1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de apl

icación es el mismo borde de dicha rueda provocando un impulso en el sentido de las agujas del reloj. Solución:
Physics
1 answer:
Sav [3K]6 days ago
5 0
The torque resulting from a force is expressed as τ= F r into the blade. The force's moment is mathematically represented as τ = F x r, where the bold terms signify vectors. We can express this in terms of magnitude as τ = F r sin θ. In our scenario, since the force is tangential to the wheel, the angle between F and the radius is 90º, with sin 90 = 1. Hence, τ= F r. The torque's direction can be determined using the right-hand rule, where fingers curling in accordance with the torque direction from force to radius, with the thumb indicating the torque's direction. For a clockwise rotation, the fingers curl in that direction, and the thumb points inward toward the blade, indicating the direction of the torque.
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An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmoni
inna [2965]

When air is forced into the open pipe,

L = \frac{nλ}{2}

where n represents any whole number such as 1,2,3,4, etc., and λ denotes the wavelength of the oscillation

This implies λ=\frac{2L} {n}

It is important to note that n=1 corresponds to the fundamental frequency, n=2 corresponds to the first harmonic, and so forth.

Thus, the third harmonic will be for n=4

With L=6m and n=4, solving for λ yields:

λ=\frac{(2)*(6)}{4} =3m

The connection between frequency (f), sound speed (c), and wavelength (λ) is given by:

c=f.λ or f= \frac{c}{λ}

Therefore, f=\frac{344}{3}

≈115 Hz

8 0
16 days ago
Consider three identical metal spheres, A, B, and C. Sphere A carries a charge of -2.0 µC; sphere B carries a charge of -6.0 µC;
inna [2965]
None of the provided options is correct. After contact, A becomes -4 µC, B remains 0 µC, and C ends with +4.0 µC. When spheres A and B touch, charges will redistribute to establish balance, resulting in A = -4 µC, B = -4 µC, C = +4.0 µC. After C and B are touched, both positive and negative charges neutralize each other, leaving A at -4 µC, B at 0 µC, and C at 0 µC.
5 0
24 days ago
A positive point charge q is placed at the center of an uncharged metal sphere insulated from the ground. The outside of the sph
Softa [2918]
B. The charge on A is -q; B has no charge. Given that a positive charge is situated at the center of an uncharged metallic sphere which is insulated and disconnected from the ground, a negative charge (-q) will appear on the inner surface A of the sphere. Should the exterior surface B be grounded, it will become neutral, resulting in no charge remaining on surface B.
4 0
18 days ago
The equation for the change in the position of a train (measured in units of length) is given by the following expression: x = ½
Keith_Richards [3138]
(B) (length)/(time³) Explanation: The term x = ½ at² + bt³ should meet dimensional consistency. This means that both bt³ and ½ at² must share the same units, which are length. To find the dimension of b, we rearrange the equation: [x] = [b]*[t]³ leads to length = [b]*time³, hence [b] = length/time³.
6 0
24 days ago
Read 2 more answers
An object is attached to a hanging unstretched ideal and massless spring and slowly lowered to its equilibrium position, a dista
Sav [3032]

Answer:

        h = 12.8 cm

Explanation:

The initial parameters are as follows:

distance = 6.4 cm

  • when the object descends, its weight matches the spring's force

        weight = spring force

         mg = ky... equation 1

  • potential energy stored in a stretched spring = work done by the spring

        mgh = 0.5 x k x h^{2}....equation 2

  • Substituting from equation 1 into equation 2

                kyh =  0.5 x k x h^{2}

                y =  0.5 x h

                2y = h

  • where y is 6.4, yielding the maximum elongation as

          h = 2 x 6.4 = 12.8 cm

6 0
1 month ago
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