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Brilliant_brown
1 month ago
5

1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de apl

icación es el mismo borde de dicha rueda provocando un impulso en el sentido de las agujas del reloj. Solución:
Physics
1 answer:
Sav [3.1K]1 month ago
5 0
The torque resulting from a force is expressed as τ= F r into the blade. The force's moment is mathematically represented as τ = F x r, where the bold terms signify vectors. We can express this in terms of magnitude as τ = F r sin θ. In our scenario, since the force is tangential to the wheel, the angle between F and the radius is 90º, with sin 90 = 1. Hence, τ= F r. The torque's direction can be determined using the right-hand rule, where fingers curling in accordance with the torque direction from force to radius, with the thumb indicating the torque's direction. For a clockwise rotation, the fingers curl in that direction, and the thumb points inward toward the blade, indicating the direction of the torque.
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A 450g mass on a spring is oscillating at 1.2Hz. The totalenergy of the oscillation is 0.51J. What is the amplitude.
Sav [3153]

Response:

A=0.199

Clarification:

We know that  

Mass of spring=m=450 g==\frac{450}{1000}=0.45 kg

Where 1 kg=1000 g

Frequency of oscillation=

\nu=1.2Hz

Energy for oscillation is 0.51 J

To determine the amplitude of oscillations.

Energy for oscillator=E=\frac{1}{2}m\omega^2A^2

Where \omega=2\pi\nu=Angular frequency

A=Amplitude

\pi=\frac{22}{7}

Using the formula

0.51=\frac{1}{2}\times 0.45(2\times \frac{22}{7}\times 1.2)^2A^2

A^2=\frac{2\times 0.51}{0.45\times (2\times \frac{22}{7}\times 1.2)^2}=0.0398

A=\sqrt{0.0398}=0.199

Therefore, the amplitude of oscillation=A=0.199

4 0
2 months ago
The surface is tilted to an angle of 37 degrees from the horizontal, as shown above in Figure 3. The blocks are each given a pus
inna [3103]

Answer:

Incomplete question: "Each block has a mass of 0.2 kg"

The velocity of the center of mass for the two-block system just prior to their collision is 2.9489 m/s

Explanation:

Provided information:

θ = angle of the surface = 37°

m = mass of each block = 0.2 kg

v = speed = 0.35 m/s

t = collision time = 0.5 s

Question: What is the velocity of the center of mass for the two-block system right before the blocks collide, vf =?

Change in momentum:

delta(P)=F*delta(t)

P_{f} -P_{i}=F*delta(t)

2m(v_{f} -v_{i})=F*delta(t)

v_{i} =0.35-0.35=0

It’s essential to calculate the required force:

F=(m+m)*g*sin\theta

Here, g = acceleration due to gravity = 9.8 m/s²

F=(0.2+0.2)*9.8*sin37=2.3591N

v_{f} =\frac{F*delta(t)}{2m} =\frac{2.3591*0.5}{2*0.2} =2.9489m/s

6 0
2 months ago
A 5.00-A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5 * 1028 free ele
Maru [3345]

Answer:

a)n= 3.125 x 10^{19 electrones.

b)J= 1.515 x 10^{6 A/m²

c)V_{d =1.114 x 10^{4m/s

d) ver explicación

Explanation:

La corriente 'I' = 5A =>5C/s

diámetro 'd'= 2.05 x 10^{-3 m

radio 'r' = d/2 => 1.025 x 10^{-3 m

número de electrones 'n'= 8.5 x 10^{28}

a) La cantidad de electrones que pasan por la bombilla cada segundo se determina mediante:

I= Q/t

Q= I x t => 5 x 1

Q= 5C

Como sabemos que: Q= ne

donde e es la carga del electrón, es decir, 1.6 x 10^{-19C

n= Q/e => 5/ 1.6 x 10^{-19

n= 3.125 x 10^{19 electrones.

b) La densidad de corriente 'J' en el cable se calcula como

J= I/A => I/πr²

J= 5 / (3.14 x (1.025x 10^{-3)²)

J= 1.515 x 10^{6 A/m²

c) La velocidad típica 'V_{d' de un electrón se expresa como:

V_{d = \frac{J}{n|q|}

    =1.515 x 10^{6 / 8.5 x 10^{28} x |-1.6 x 10^{-19|

V_{d =1.114 x 10^{4m/s

d) De acuerdo con estas ecuaciones,

J= I/A

V_{d = \frac{J}{n|q|} =\frac{I}{nA|q|}

Si utilizaras un cable de doble diámetro, ¿cuáles de las respuestas anteriores cambiarían? ¿Aumentarían o disminuirían?

5 0
3 months ago
Read 2 more answers
A horizontal jet of water is made to hit a vertical wall with a negligible rebound. If the speed of water from the jet is 'v', t
serg [3582]
F = π/4 ρ d² v²

Explanation:

The formula for force is mass multiplied by acceleration:

F = ma

Acceleration is defined as the change in velocity over the change in time:

F = m Δv / Δt

Since there is no rebound effect, Δv is equal to v.

F = m v / Δt

Mass can be calculated as density multiplied by volume:

F = ρ V v / Δt

Flow rate describes the volume per time:

F = ρ Q v

Flow rate is determined by velocity multiplied by the cross-sectional area:

F = ρ (v A) v

This simplifies to F = ρ A v²

The area of a circle is calculated as pi times the square of the radius, or as pi/4 times the diameter squared:

F = ρ (π/4 d²) v²

Hence, F = π/4 ρ d² v²

3 0
1 month ago
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