In a novel from 1866 the author describes a spaceship that is blasted out of a cannon with a speed of about 11.000 m/s. The spac
1 answer:
Answer:
Explanation:
We start with the fact that
Initially, the spacecraft was at rest, u = 0The final velocity of the rocket is given as v = 11 m/sThe distance that the rocket covers during acceleration is given as d = 213 mWe seek to determine the acceleration that the occupants of the spacecraft experience during launch, which is derived from the principles of kinematics. By applying thethird motion equation we can find the acceleration.
Thus, the acceleration felt by those inside the spacecraft is .
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Answer:
-611.32 N/C
0.43723 m
Explanation:
k = Coulomb constant =
q = Charge = -4.25 nC
r = Distance from particle = 0.25 m
The electric field can be calculated using
The calculated magnitude is 611.32 N/C
The electric field direction is vertically downward due to the negative charge.
The distance from the electric field source is 1.71436 m
Let's assume that the initial quantity of nuclides is 100.
If 7/8 of 100 has decayed, we conclude that 87.5 has decayed.
This means that 1/8 remains from the original amount of 100, which results in 12.5 remaining.
To find out how many Half-lives it took for the sample to drop from 100 to 12.5, we can establish that 3 Half-Lives have elapsed.
Given that each Half-Life is 80 seconds, the total time taken would be 240 seconds.
Therefore, the conclusion is that it will take 240 seconds.
If 7/8 of 100 has decayed, we conclude that 87.5 has decayed.
This means that 1/8 remains from the original amount of 100, which results in 12.5 remaining.
To find out how many Half-lives it took for the sample to drop from 100 to 12.5, we can establish that 3 Half-Lives have elapsed.
Given that each Half-Life is 80 seconds, the total time taken would be 240 seconds.