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Nuetrik
8 days ago
8

The gas tank of Dave’s car has a capacity of 12 gallons. The tank was 38 full before Dave filled it to capacity. It cost him $2.

50 per gallon of gas. How much did Dave spend, in dollars, to fill the tank to capacity?
Physics
2 answers:
Keith_Richards [1K]8 days ago
7 0

Answer:

$ 30

Explanation:

The tank has a total capacity of 12 gallons

The price for a single gallon is $2.50

Calculating the total for 12 gallons: 12 x 2.50 = $ 30

Therefore, filling the tank with 12 gallons costs $ 30.

Sav [1.1K]8 days ago
5 0

Answer:

$ 18.75

Explanation:

Given:

Dave's car has a capacity of 12 gallons.

If the tank is at 3/8 full prior to filling:

The cost of gasoline per gallon is $2.50.

The volume Dave needs to fill:

=1 - \dfrac{3}{8}

=\dfrac{5}{8} of full tank

=\dfrac{5}{8}\times 12

Dave must fill 7.5 gallons.

Total amount Dave will pay:

7.5 gallons x $2.50 =

$ 18.75

Thus, Dave will spend $ 18.75 to completely fill the tank.

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A person is rowing across the river with a velocity of 4.5 km/hr northward. The river is flowing eastward at 3.5 km/hr (Figure 4
Yuliya22 [1153]

Answer: Her velocity magnitude (v) relative to the shore is 5.70 km/h.

Explanation:

Let Q be the speed of the boat, and P be the speed of the river flow.

R represents the resultant velocity combining boat velocity and river current.

According to vector addition using the law of triangles:

R=\sqrt{P^2+Q^2+2PQCos\theta}

From the diagram:

P = 3.5 km/h, Q = 4.5 km/h

\theta= 90^o

R=\sqrt{P^2+Q^2+2PQCos\theta}=\sqrt{(3.5)^2+(4.5)^2+3.5\times 4.5\times cos90^o}=5.70

(Cos90^o=0),(sin 90^o=1)

\alpha =tan^{-1}\frac{Qsin\theta}{P+Qcos\theta}=tan^{-1}\frac{4.5 sin 90^o}{3.5+4.5 cos90^o}=tan^{-1}\frac{4.5}{3.5}=52.12^o

Therefore, her velocity magnitude relative to the shore is 5.70 km/h.

8 0
17 days ago
A bus slows down uniformly from 75.0 km/h to 0 km/h in 21 s. How far does it travel before stopping?
Yuliya22 [1153]

1 hour = 3,600 seconds
1 km = 1,000 meters

75 km/hour = (75,000/3,600) m/s = 20-5/6 m/s

The mean speed during the deceleration is

                                   (1/2)(20-5/6 + 0) = 10-5/12 m/s.

Traveling at this average speed for 21 seconds,
the bus covers

                        (10-5/12) × (21) = 218.75 meters.

7 0
15 days ago
Read 2 more answers
An object is at rest on the ground. The object experiences a downward gravitational force from Earth. Which of the following pre
Yuliya22 [1153]

Answer:

A) and B) are valid.

Explanation:

When an object remains at rest, it is indicative that no net force acts upon it.

The downward gravitational force from Earth must be counterbalanced by an upward force of equal magnitude in order to maintain rest.

This upward force is provided by the normal force, which adjusts to satisfy Newton’s 2nd Law and is always perpendicular to the surface supporting the object (in this instance, the ground).

At the molecular level, this normal force comes from the ground's bonded molecules acting like tiny springs, compressed by the object’s molecules, providing an upward restorative force.

Thus, statements A) and B) are true.

6 0
2 days ago
Read 2 more answers
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
serg [1198]

Answer:

b) TA = TB = TC

Explanation:

  • When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
  • During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
  • The equilibrium state will be established once this equation is satisfied:

       \Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )

  • Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
  • When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
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8 0
6 days ago
A string is stretched by two equal but opposite forces f newton each what is tension in string
Maru [1056]

The string does not experience any force of tension, as it balances two forces acting in the same direction. Hence, the tension is zero.

Explanation:

If tension existed in the string, it would mean that two equal but opposite forces are exerting pull in contrary directions.

When a force of f newtons is applied from the right and another force of f newtons from the left, the resulting action occurs through one force. Because there is action on the same string in opposing directions, the tension in the string can only be equal to the magnitude of the string itself.

Therefore, the string indeed has no tension since it is dealing with two forces acting in the same direction. Thus, the tension is zero.

8 0
4 days ago
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