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Anastaziya
5 days ago
5

A probe from earth, with a mass of 106 kg, is in orbit around planet Pud in another solar system. Pud has a radius of 106 m and

the probe has an orbital radius of 107 m (its orbit is circular). If the speed of the probe in orbit is 1 km/s, what is the acceleration due to g
Physics
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If you wished to warm 100 kg of water by 15 degrees celsius for your bath, how much heat would be required? (give your answer in
kicyunya [3294]
To respond to the previous question:
<span>Q = heat quantity (kJ) </span>
<span>cp = specific heat (kJ/kg.K) = 4.187 kJ/kgK </span>
<span>m = weight (kg) </span>
<span>dT = temperature change between hot and cold water (K). Note: dt in °C is identical to dt in Kelvin </span>

<span>Q = 100kg * (4.187 kJ/kgK) * 15 K </span>
<span>Q = 6,280.5 KJ = 6,280,500 J = 1,501,075.5 cal</span>
6 0
1 month ago
If Siobhan hits a 0.25 kg volleyball with 0.5 N of force, what is the acceleration of the ball?
Keith_Richards [3271]

Answer:

2 m/s²

Explanation:

8 0
1 month ago
Read 2 more answers
A jogger accelerates from rest to 3.0 m/s in 2.0 s. A car accelerates from 38.0 to 41.0 m/s also in 2.0 s. (a) Find the accelera
Sav [3153]

Answer:

a) The jogger's acceleration is 1.5 m/s²

b) The car's acceleration is also 1.5 m/s²

c) Yes, the car covers a distance 76 m greater than the jogger.

Explanation:

a) Acceleration is the change in velocity over a given time interval:

a = (final velocity - initial velocity) / time

For the jogger:

a = (3.0 m/s - 0 m/s) / 2.0 s = 1.5 m/s²

b) For the car:

a = (41.0 m/s - 38.0 m/s) / 2.0 s = 1.5 m/s²

c) To find how far the car has traveled after 2 seconds, use the formula for position under acceleration along a straight path:

x = x₀ + v₀ t + ½ a t²

where

x = position at time t

x₀ = initial position

v₀ = initial velocity

t = elapsed time

a = acceleration

Assuming x₀ = 0 (origin at car's starting point):

x = 38.0 m/s × 2 s + ½ × 1.5 m/s² × (2.0 s)²

x = 79 m

Similarly, position of the jogger after 2 seconds is:

x = 0 m/s × 2 s + ½ × 1.5 m/s² × (2.0 s)² = 3 m

The difference traveled by the car compared to the jogger is 79 m - 3 m = 76 m

4 0
3 months ago
A permeability test was run on a compacted sample of dirty sandy gravel. The sample was 175 mm long and the diameter of the mold
Maru [3345]

Answer:

(a). The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(b). The seepage velocity is 0.0330 cm/s.

(c). The discharge velocity during the test is 0.0187 cm/s.

Explanation:

Given that,

Length = 175 mm

Diameter = 175 mm

Time = 90 sec

Volume= 405 cm³

We need to calculate the discharge

Using formula of discharge

Q=\dfrac{V}{t}

Insert the values into the formula

Q=\dfrac{405}{90}

Q=4.5\ cm^3/s

(a). We will compute the coefficient of permeability

Applying the formula for permeability

Q=kiA

k=\dfrac{Q}{iA}

k=\dfrac{Ql}{Ah}

Where, Q=discharge

l = length

A = cross-sectional area

h=constant head that causes flow

Plugging the value into the formula

k=\dfrac{4.5\times175\times10^{-1}}{\dfrac{\pi(175\times10^{-1})^2}{4}\times38}

k=8.6\times10^{-3}\ cm/s

The coefficient of permeability measures as 8.6\times10^{-3}\ cm/s.

(c). To ascertain the discharge velocity during the testing phase

Utilizing the discharge velocity formula

v=ki

v=\dfrac{kh}{l}

Substituting the values into the equation

v=\dfrac{8.6\times10^{-3}\times38}{17.5}

v=0.0187\ cm/s

The discharge velocity during the test measures 0.0187 cm/s.

Thus, (a). The coefficient of permeability is 8.6\times10^{-3}\ cm/s.

(b). The seepage velocity computes at 0.0330 cm/s.

(c). The observed discharge velocity during the test equals 0.0187 cm/s.

8 0
2 months ago
Which of the following is (are) true of ligand-gated ion channels?
Ostrovityanka [3204]

Answer:

The properties of ligand-gated ion channels include:

a. They play a crucial role in the nervous system by altering sodium and calcium levels within cells.  

b. Their significance is primarily linked to the nervous system.

c. They are vital for the nervous system, responsible for modulating sodium and calcium levels in cells, and they respond to chemical signals by either opening or closing.

Explanation:

Ligand-gated ion channels (LICs or LGICs), often called ionotropic receptors, represent a class of trans-membrane ion-channel proteins that open to permit the flow of ions like Na+, K+, Ca2+, and/or Cl− across membranes in reaction to the binding of chemical signals. Their function contrasts with that of voltage-gated ion channels, which are triggered by changes in voltage across membranes (i.e., when depolarization occurs) and are responsive to membrane potentials. In comparison to GPCRs that utilize secondary messengers, ligand-gated channels operate upon the binding of a ligand (a specific chemical signal). Both types of channels are essential for the effective activation of the post-synaptic neuron.

3 0
2 months ago
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