Answer:
$ 18.75
Explanation:
Given:
Dave's car has a capacity of 12 gallons.
If the tank is at 3/8 full prior to filling:
The cost of gasoline per gallon is $2.50.
The volume Dave needs to fill:
=
=
of full tank
=
Dave must fill 7.5 gallons.
Total amount Dave will pay:
7.5 gallons x $2.50 =
$ 18.75
Thus, Dave will spend $ 18.75 to completely fill the tank.
Response: Liquids conform to the shape of their container, yet they maintain a specific volume. Similarly, gases adjust their shape based on their container, but the volume of a gas is variable depending on the containment it occupies.
Explanation:
Answer:
This excerpt is considered part of the resolution since it illustrates the events following the climax. It resolves the conflict, bringing the narrative to a conclusion.
Explanation: because I am intelligent, that's why.
Answer:
A. Reference the figure.
B. The resultant force acting on the crate is
C. Initially, we should determine the acceleration of the crate using this kinematics equation:
The crate's mass can be derived through Newton’s Second Law:
Response:
a) 8.99*10³ V b) 4.5*10⁻² J c) 0 d) 0
Clarification:
a)
- Electrostatic potential V is defined as the work achieved per unit charge, as conducted by the electrostatic force, which moves a distance d from infinity (considered the reference zero level).
- For a point charge, it can be represented mathematically:
- Since electrostatic force behaves linearly concerning charge, we can apply the superposition principle.
- This principle states that the cumulative potential at any given point is simply the sum of the individual potentials contributed by various charges, as if the others were absent.
- In our specific configuration, due to symmetry, the potential at each corner of the triangle is simply double that of the potential resulting from any charge at another corner, as demonstrated:
- The potential at point C registers as 8.99*10³ V.
b)
- The energy needed to move a positive charge of 5μC from infinity to point C is calculated by multiplying the potential at that point by the charge, explained below:
- The work required amounts to 0.045 J.
c)
- If we substitute one of the charges at point C with one of the opposite charge of equal magnitude, the following equation emerges:
- This indicates that the potential arising from both charges results in 0 at point C.
d)
- With point C's potential calculated as 0 and assuming V=0 at infinity too, we derive that bringing the charge of 5μC from infinity to point C requires no work, as there is no potential difference between the two locations.
