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3 months ago

Explain the versatility of epithelial tissue

2 answers:

8 0

Epithelial cells are categorized based on three criteria: 1. Morphology. 2. Layering. 3. Functionality. This is a core element for the mehe family and significantly contributes to actions like nodding your head.

Yuliya22 [3.3K]3 months ago

6 0

Answer:

Explanation:

Epithelial tissues serve to cover surfaces of the body, providing linings for body cavities and internal organs. Additionally, they create a defensive barrier between the body and the external environment.

These tissues are multifunctional, consisting of tightly packed cells that closely associate with one another. The structure and functionality of epithelial cells differ between the upper and lower surfaces. Given their diverse roles—such as shielding, secretion, transportation, filtration, selective absorption, and sensory perception—these tissues are recognized for their versatility.

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A 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. It takes 6060 NN to loosen the bolt wh

Softa [3030]

Complete Question

A 30 cm cm wrench is employed to loosen a bolt, with force applied 0.30m from the bolt. It requires 60 N to loosen the bolt when force is applied perpendicular to the wrench. How much force would be necessary if the force were applied at a 30-degree angle from perpendicular?

Response:

The strength needed is $F_{\theta } = 69.28 \ N$

Clarification:

According to the problem, we know that

The length of the wrench is $L = 30 cm = \frac{30}{100} = 0.3 \ m$

The distance from the bolt is $d = 0.30 m$

The force necessary to loosen the bolt is $F = 60 N$

The angle of application is $\theta = 30 ^o$

Generally, the torque required for loosening the bolt is defined as

$\tau = F * d$

$\tau = 60 * 0.3$

$\tau = 18 Nm$

Now for the bolt to loosen at $\theta$ the torque at 90° must equal that at $\theta$

Thus, the torque at $\theta$ is represented mathematically as

$\tau = F_{\theta }d cos \theta$

substituting values gives us

$18 = F_{\theta } * 0.3 cos (30)$

$F_{\theta } = \frac{18}{0.3 cos (30)}$

$F_{\theta } = 69.28 \ N$

7 0

2 months ago

A plane monochromatic radio wave (λ = 0.3 m) travels in vacuum along the positive x-axis, with a time-averaged intensity I = 45

serg [3582]

The magnetic field is calculated to be -6.137 × T. Explanation: Given the radio wave wavelength of λ = 0.3 m and an intensity of I = 45 W/m² at times t = 0 and t = 1.5 ns, we determine Bz at the origin. We use the intensity formula relating to the electric field, which incorporates the known intensity of 45, the speed of light c = 3 × m/s², and ∈o as 8.85 × C²/N.m², leading us to E = 184.15. Consequently, applying the equations, we find B = -6.137 × T at the z-axis.

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3 months ago