Answer: The apparent density of ethylene glycol 3350 is calculated as 3350 = 17g/15.6mL= 1.09g/mL
The specific gravity of the mixture is 1.01
Explanation:
Specific gravity refers to the density of a substance compared to that of a reference substance, typically water.
Specific gravity = density of substance/density of water
The density of a substance measures the mass of that substance relative to its volume.
Density = Mass/Volume
The density of water is known to be 1.00 g/mL,
Apparent density of ethylene glycol 3350 is assessed as mass/volume
the volume of ethylene glycol = total volume of mixture - volume occupied by water
volume of ethylene glycol = 195.6 - 180 = 15.6 mL
Apparent density of ethylene glycol 3350 = 17g/15.6mL= 1.09g/mL
mass of water is computed as density of water multiplied by volume of water
mass of water = 1.00g/mL * 180mL = 180 g
Total mass of solution = mass of substance plus mass of water = (17 + 180)g = 197g
Density of the mixture = total mass of the mixture divided by its volume
Density of mixture = 197 g / 195.6 mL = 1.01 g/mL
To find the specific gravity of the mixture, use the formula:
specific gravity of mixture = density of mixture divided by density of water
specific gravity of mixture = 1.01g/mL / 1.00g/mL
specific gravity of mixture = 1.01
