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joja
22 days ago
6

Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. Cu(s)

+2AgNO3(aq)⟶2Ag(s)+Cu(NO3)2(aq)
Chemistry
1 answer:
alisha [2.7K]22 days ago
4 0

Answer: Copper is being oxidized and acts as a reducing agent. In contrast, silver is being reduced, functioning as the oxidizing agent.

Explanation:

An oxidation reaction involves the loss of electrons by an atom. Here, the oxidation state of the atom rises.

X\rightarrow X^{n+}+ne^-

Conversely, a reduction reaction is characterized by an atom gaining electrons, resulting in a decrease in its oxidation state.

X^{n+}+ne^-\rightarrow X

Oxidizing agents are those that facilitate the oxidation of another substance while themselves being reduced. These substances participate in reduction reactions.

Reducing agentsare defined as those that reduce other substances while undergoing oxidation themselves. They also take part in reduction reactions.

In the provided chemical reaction:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The associated half-reactions for the above process are:

Oxidation half reaction:  Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

Reduction half reaction:  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

From the reactions outlined, copper is losing electrons. Consequently, it is oxidized and regarded as a reducing agent.

Silver is acquiring electrons, thus it is being reduced and viewed as an oxidizing agent.

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The final overall chemical equation is Upper Ca upper O (s) plus upper C upper O subscript 2 (g) right arrow upper C a upper C u
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Answer:

The enthalpy of the second intermediate equation is altered by halving its value and changing the sign.

Explanation:

Let's examine both the first and second intermediate reactions alongside the overall equation concerning the examined process;

First reaction;

Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ

Second reaction;

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Thus, the overall reaction becomes;

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According to Hess's law, which states that the total heat change in a reaction is equal to the sum of the heat changes for each step, we cannot simply sum the enthalpies for this overall reaction. Instead, we obtain the overall enthalpy by halving the second intermediate reaction's enthalpy and changing its sign before adding, as illustrated below;

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Arrange the sublevels in ascending order by the number of electrons they can contain. p sublevel s sublevel d sublevel f subleve
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The electronic configuration of an atom details how electrons are organized across various shells and sublevels.

There are four categories of sublevels: s, p, d, and f. Each of these sublevels contains orbitals, which are regions with a high likelihood of containing an electron, with each orbital capable of holding a maximum of 2 electrons.

As a result,

s-sublevel possesses 1 orbital, allowing for a maximum of 2 electrons.

p-sublevel has 3 orbitals, accommodating a maximum of 6 electrons.

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3 0
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