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Shalnov
1 month ago
12

The power rating of an electric lawn mower is 2000 watts if lawnmower is used for 120 seconds how many joules of work van it do

Physics
1 answer:
Softa [3K]1 month ago
4 0
1 watt equals 1 joule per second

A 2,000-watt mower therefore delivers 2,000 joules every second

                     Running that output for 120 seconds

                  yields (2,000 joules/sec) × (120 sec)

                  =   240,000 joules .
        
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Bianca is standing at x =600m. Firecracker 1, at the origin, and firecracker 2, at x =900m, explode simultaneously. The flash fr
kicyunya [3294]
Given that Bianca is positioned at a distance of 600m from the origin, the time for the flash from firecracker 1 to reach her eyes is 4.0 μs. Therefore, the time taken for the flash from firecracker 2, located at 900m, is to be calculated, leading to the conclusion that the flash will be observed at the designated time.
4 0
1 month ago
Three equal negative point charges are placed at three of the corners of a square of side d. What is the magnitude of the net el
Ostrovityanka [3204]
<span>this might be useful
Regarding the field, the two charges placed opposite cancel each other out!
Therefore, E = kQ / d² = k * Q / (d/√2)² = 2*k*Q / d² ◄
given k = 8.99×10^9 N·m²/C²,
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8 0
3 months ago
Read 2 more answers
Wire A has the same length and twice the radius of wire B. Both wires are made of the same material and carry the same current.
serg [3582]

Answer:

V_A= \frac{I_A}{n_A e A_A}= \frac{I}{ne 4A_B}= \frac{1}{4} \frac{I}{neA_B}

V_B= \frac{I_B}{n_B e A_B}= \frac{I}{ne A_B}

Consequently, we find that:

V_A = \frac{1}{4} V_B

Thus, the most suitable answer would be:

a. vA = vB/4

Explanation:

In this situation, we can establish the following conditions:

L_A = L_B =L both wires share the same length

both wires carry an identical currentI_A = I_B =I

Both wires are constructed of the same material, indicating that the electron density (n) remains constant across both wires

n_A = n_B =n

We also know that r_A = 2 r_B where r signifies the radius.

Given that wires are cylindrical in shape, we can determine the area for each case:

A_A= \pi r^2_A = \pi (2r_B)^2 = 4 \pi r^2_B= 4 A_B

A_B = \pi r^2_B

Thus, we conclude that

A_A = 4 A_B

Now we are aware that the drift velocity of an electron in a wire can be described by:

v_d = \frac{I}{neA}

Where I denotes the current, n is the electron density, e represents the electron charge, and A signifies the area.

By substituting, we arrive at:

V_A= \frac{I_A}{n_A e A_A}= \frac{I}{ne 4A_B}= \frac{1}{4} \frac{I}{neA_B}

V_B= \frac{I_B}{n_B e A_B}= \frac{I}{ne A_B}

So we observe that:

V_A = \frac{1}{4} V_B

Thus, the most fitting answer is:

a. vA = vB/4

6 0
1 month ago
A trained sea lion slides from rest down a long
Keith_Richards [3271]

Answer:

1.5 m/s²

Explanation:

Begin by sketching a free body diagram.  Three forces are at play on the sea lion: the force of gravity acting downwards, the normal force that is perpendicular to the ramp, and the frictional force parallel to the ramp.

Considering the forces perpendicular to the incline:

∑F = ma

N − mg cos θ = 0

This gives us N = mg cos θ

Next, examining the forces parallel to the incline:

∑F = ma

mg sin θ − Nμ = ma

Substituting for N yields:

mg sin θ − (mg cos θ) μ = ma

g sin θ − g cos θ μ = a

hence a = g (sin θ − μ cos θ)

If we set θ = 23° and μ = 0.26:

a = 9.8 (sin 23 − 0.26 cos 23)

this results in a = 1.48

When rounded to two significant figures, the acceleration of the sea lion is 1.5 m/s².

5 0
1 month ago
Using evidence from the article, defend the concept that Earth’s magnetic poles have swapped places over time.
Maru [3345]

Answer: Research has revealed signs of the Earth's magnetic field flipping in ocean floor rocks, especially at tectonic plate boundaries. These rocks exhibit alternating polarity because of the magnetization that happened as they solidified. Through radio metric dating, scientists suggest these reversals take place roughly every few hundred thousand years.

Explanation:

6 0
1 month ago
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