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ivanzaharov
12 days ago
8

How many moles of n2(g) would contain exactly 4.0 moles of nitrogen atoms?

Chemistry
2 answers:
lions [1K]12 days ago
4 0

Answer: The moles of N_2 are 2 moles.

Explanation: Given,

Moles of nitrogen atoms = 4 moles.

First, we need to determine the total number of nitrogen atoms.

Since 1 mole of nitrogen atom has 6.022\times 10^{23} nitrogen atoms,

Then 4 moles of nitrogen atom contain 4\times 6.022\times 10^{23} nitrogen atoms.

Next, we calculate the moles of N_2 atoms.

As 2\times 6.022\times 10^{23} number of nitrogen atoms is present in 1 mole of N_2 atoms,

And 4\times 6.022\times 10^{23} nitrogen atoms exist in \frac{4\times 6.022\times 10^{23}}{2\times 6.022\times 10^{23}}=2 moles of N_2 atoms.

Thus, the number of moles of N_2 atoms is 2 moles.

VMariaS [1K]12 days ago
4 0

Each nitrogen molecule consists of 2 nitrogen atoms.
Thus, 2 moles of nitrogen gas molecules result in 4 moles of nitrogen atoms. The answer is 2 moles.

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A chemist is studying the following reaction: NO + NO2 ⇌ N2O3. She places a mixture of NO and NO2 in a sealed container and meas
castortr0y [927]

Answer:

The forward reaction will keep occurring until all NO or all NO₂ is consumed.

Clarification:

  • According to Le Châtelier's principle, when a system at equilibrium experiences a disturbance from an outside source, the system will adjust to counteract this disturbance and restore equilibrium.

  • Thus, removing the product (N₂O₃) from the system effectively lowers the product concentration, prompting the reaction to shift forward and generate additional product in order to alleviate the strain caused by the removal of N₂O₃.

  • Consequently, the reaction will proceed forward until all of either NO or NO₂ is depleted.

5 0
2 days ago
A tritium nucleus is formed by combining two neutrons and a proton. the mass of this nucleus is 9.106 × 10–3 universal mass unit
lions [1003]
E = mc²

where E = energy produced

m = mass of the nucleus

C = speed of light

m = 9.106 x 10⁻³ x 1.67 x 10⁻²⁷ kg

C = 3 x 10⁸ m/s, thus C² = 9 x 10¹⁶

E = 1.37 x 10⁻¹² J

7 0
5 days ago
Read 2 more answers
A laboratory analysis of an unknown sample yields 74.0% carbon, 7.4% hydrogen, 8.6% nitrogen, and 10.0% oxygen. What is the empi
Tems11 [854]
Assuming we have a 100g sample, the mass of each element is as follows:
C: 74 g
H: 7.4 g
N: 8.6 g
O: 10 g
Next, we calculate the moles of each by dividing the mass of each element by its molar mass:
C: (74 / 12) = 6.17
H: (7.4 / 1) = 7.4
N: (8.6 / 14) = 0.61
O: (10 / 16) = 0.625
Now, we take the smallest value to determine the ratio:
C: 10
H: 12
N: 1
O: 1
Thus, the empirical formula can be expressed as
C10H12NO
3 0
6 days ago
Find the age ttt of a sample, if the total mass of carbon in the sample is mcmcm_c, the activity of the sample is AAA, the curre
castortr0y [927]

Answer:

Explanation:

In a desert cave, an artifact has been discovered. The anthropologists investigating this artifact want to determine its age. They note that the current activity level of the artifact is 9.25 decays/s, and the carbon mass present is 0.100 kg. To ascertain the artifact's age, they will employ specific constants:

r=1.2

The formula for carbon 14 activity is

A=A_0e^{\lambda t}

where,

A_0 is the initial activity of the substance

Now, solve for t

-\lambda t=In\frac{A}{A_0}

t=-\frac{1}{\lambda} In(\frac{A}{A_0} )

=-\frac{1}{\lambda} In(\frac{A}{\lambda r(\frac{m_c}{m_a} )} )

since,

A_0=\lambda r(\frac{m_c}{m_a} )

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

Thus, the age of the artifact is

=-\frac{1}{\lambda} In(\frac{A\ m_a}{\lambda r m_c} )

=-\frac{1}{1.21\times 10^{-4}} In(\frac{(9.25)(2.32\times 10^{-26}}{1.21\times 10^{-4}(\frac{1}{3.15569\times10^7} )(1.2\times 10^{-12})(0.100)}} )\\\\=6303.4 \ years

to two significant figures = 6300 years

4 0
6 days ago
the image above shows a chamber with a fixed volume filled with gas at a pressure of 1560 mmHg and a temperature of 445.0 K. If
VMariaS [1037]

Answer:

The new gas pressure within the chamber registers at 1,093.75 mmHg

Explanation:

The Gay-Lussac Law establishes a relationship between a gas's pressure and temperature when volume remains constant. This principle asserts that gas pressure is directly tied to its temperature: as temperature increases, pressure rises, and conversely, as temperature falls, pressure also diminishes. Therefore, the Gay-Lussac law can be depicted mathematically as:

\frac{P}{T} =k

Given an initial and final state of gas, we can apply the following formula:

\frac{P1}{T1} =\frac{P2}{T2}

In this scenario:

  • P1= 1560 mmHg
  • T1= 445 K
  • P2=?
  • T2= 312 K
<psubstituting:>

\frac{1560 mmHg}{445 K} =\frac{P2}{312 K}

Calculating:

P2=\frac{1560 mmHg}{445 K} *312K

P2=1,093.75 mmHg

The new gas pressure inside the chamber is 1,093.75 mmHg

</psubstituting:>
7 0
14 days ago
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