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3 months ago

How many moles of n2(g) would contain exactly 4.0 moles of nitrogen atoms?

Chemistry

2 answers:

lions [2.9K]3 months ago

4 0

Answer: The moles of $N_2$ are 2 moles.

Explanation: Given,

Moles of nitrogen atoms = 4 moles.

First, we need to determine the total number of nitrogen atoms.

Since 1 mole of nitrogen atom has $6.022\times 10^{23}$ nitrogen atoms,

Then 4 moles of nitrogen atom contain $4\times 6.022\times 10^{23}$ nitrogen atoms.

Next, we calculate the moles of $N_2$ atoms.

As $2\times 6.022\times 10^{23}$ number of nitrogen atoms is present in 1 mole of $N_2$ atoms,

And $4\times 6.022\times 10^{23}$ nitrogen atoms exist in $\frac{4\times 6.022\times 10^{23}}{2\times 6.022\times 10^{23}}=2$ moles of $N_2$ atoms.

Thus, the number of moles of $N_2$ atoms is 2 moles.

VMariaS [2.9K]3 months ago

4 0

Each nitrogen molecule consists of 2 nitrogen atoms.
Thus, 2 moles of nitrogen gas molecules result in 4 moles of nitrogen atoms. The answer is 2 moles.

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2 months ago

Citric acid is a naturally occurring compound. what orbitals are used to form each indicated bond? be sure to answer all parts.2

alisha [2963]

Response: Below are the orbitals responsible for each bond identified in citric acid per the attachment.

Response 1) σ Bond a: Carbon uses $SP^{2}$ and Oxygen employs $SP^{2}$ .

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Response 2) π Bond a: Both Carbon and Oxygen have π orbitals.

Clarification: The π-bond at position 'a' consists of interactions between the π orbitals of carbon and oxygen.

Response 3) Bond b: Oxygen $SP^{3}$ and Hydrogen solely utilizes the S orbital.

Clarification: The bonding at position 'b' includes oxygen and hydrogen atoms, with hydrogen utilizing its S orbital.

Response 4) Bond c: Carbon is $SP^{3}$ and Oxygen is also $SP^{3}$ .

Clarification: The bonding process at position 'c' involves both carbon and oxygen atoms with their respective hybrid orbitals.

Response 5) Bond d: Carbon atom has $SP^{3}$ and the second carbon has $SP^{3}$ .

Clarification: In position 'd', the bond formed between carbon atoms is $SP^{3}$ , utilizing orbitals that underwent $SP^{3}$ hybridization which are $SP^{3}$ .

Response 6) Bond e: C1 has O $SP^{2}$ .

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3 months ago

HCl(aq)+NaOH(aq)→NaCl(aq)+H2O(l)

Alekssandra [3086]

Answer:

Quantity of $H_{2}O$ generated will be reduced to fifty percent of its initial amount.

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In accordance with the balanced equation, 1 mol of HCl interacts with 1 mol of NaOH leading to the formation of 1 mol of $H_{2}O$

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3 months ago