2C3H6 (g) + 2NH3 (g) + 3O2 (G) -> 2C3H3N (g) + 6H2O (g)
To begin, this isn't really a chemistry forum, but anyway.
This represents a limiting reagent scenario.
Set it up as a Dimensional Analysis issue.
Begin with your desired outcome.
Your goal is to find the mass of acrylonitrile (C3H3N)
so you should initiate with that (I'll abbreviate Acrylonitrile as ACL for convenience)
(g) = (53 g of ACL/1mol ACL) (2 mols ACL/2 mol C3H6)/ (1mol C3H6/42 grams) (15.0 grams)
If you calculate that, you will find that 15 grams of C3H6 yields 18.9 grams of acrylonitrile produced.
Utilize the same approach for the remaining two reactants.
So, I figured it out, and for
oxygen, I calculated 11.04 grams
and for ammonia, I calculated 15.29 grams
This means that the maximum possible production is 11.04 grams, since to create any additional amount, more O2 would be necessary, but with only 10 grams available, that's the upper limit for this reaction.
The other two reactants are in excess.
Please rate as brainliest!