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IrinaVladis
3 months ago
5

8) A soccer goal is 2.44 m high. A player kicks the ball at a distance 10.0 m from the goal at an angle of 25.0°. The ball hits

the crossbar at the top of the goal. What is the initial speed of the soccer ball?
Physics
1 answer:
Yuliya22 [3.3K]3 months ago
6 0
The soccer ball's initial speed stands at 16.38 m/s. Given that the vertical distance is y = 2.44 m, the horizontal span x = 10.0 m, and the angle of launch θ = 25.0°. The initial velocity comprises two components, Vₓ and V. The calculations are as follows: Vₓ = V cosθ and V = V sinθ. The formula for horizontal distance becomes x = Vₓt. Since g is deemed 0, we can state that: x = Vₓt or 10 = V cos 25 * t. Solving for V gives us 10 = 0.906V * t, thus V * t = 10 / 0.906 = 11.038 m. Regarding the vertical distance (with g being negative due to the upward movement opposing gravity), we use y = V sinθ * t - 1/2 * g * t². Following through with the calculations leads us to determine that the soccer ball's initial speed is indeed 16.38 m/s.
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