The combined mass of Laura and the sled sums up to 887.5 kgExplanation: To compute the total weight from Laura's weight plus the drag on the sled, we can determine the force as follows: =(400 + 310) N = 710 N. According to Newton's second law of motion, ''the rate of change of momentum is directly related to the force applied.'' Here, m represents Laura's mass and m the sled's mass. Thus, the combined mass is calculated as follows: given V = Δv = 4-0 = 4m/s, with t = 5 s. Consequently, the mass of Laura and the sled together results in 887.5 kg.
Depth = 5.0 × 10^2 m
Density of seawater = 1.025 x 10^3
Pd = Po + pgh
Standard atmospheric pressure is Patm = 1.01325 x 10^5 Pa
Since the pressure inside the hull is normal, we can disregard Po.
Thus, Pd = pgh = 1.025 x 10^3 x 9.8 x 5.0 x 10^2 = 50.225 x 10^5
Now calculating Pd / Patm gives us 50.225 x 10^5 / 1.01325 x 10^5 = 49.56
This indicates the pressure is 49.56 times greater.
Answer: since resistance is influenced by length, the resistance will be equally distributed as the wire is cut into two equal parts, resulting in
4.5 * 10^-3 ohm.
Explanation:
Answer:
B ) Ascend using my buddy's alternative air source / perform an emergency swimming ascent
Explanation:
From the details given, it's clear the buddy is nearby and thus the alternative air source can be utilized easily. Furthermore, the diver is closer to the water's surface than their buddy, making a controlled emergency ascent preferred in this situation.
Answer:
If the starting and ending points are identical, the overall work equals zero.
Explanation:
Option (D) is correct.
A force is considered conservative when the work performed by it while moving an object from point A to point B does not rely on the path taken and remains consistent across all paths. The work done is determined solely by the initial and final locations of the particle. Thus, when the initial and final positions in a conservative field coincide, the work is said to be zero.
