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MA_775_DIABLO
3 months ago
11

A metal object with a mass of 19g is heated to 96c, then transferred to a calorimeter containg 75g of water at 18c. the water an

d metal object reach a final temperature of 22c.
a. what is the specific heat of this metal object?
Physics
2 answers:
Yuliya22 [3.3K]3 months ago
6 0

Let Cp represent the specific heat of the metal object. To find this, we can set up a heat balance equation (heat lost by metal = heat gained by water):

- 19g * Cp * (22degC – 96degC) = 75g * 4.184J/g degC * (22degC - 18degC)

<span>Cp = 0.893 J/g degC</span>

serg [3.5K]3 months ago
4 0

Result:


The specific heat of the metal = 0.893 J/g°C

Explanation and calculation:

Heat quantity = mass × specific heat capacity × temperature change

ΔQ = Mcθ

Heat released by the metal = Heat absorbed by the water

Heat given off by the metal

= mass of metal × specific heat of metal × temperature difference

= 19 x specific heat × (22 - 96)

= 1406 × specific heat

Heat gained by water

= mass of water × specific heat of water × temperature difference

= 75 x 4.186 x (22 - 18)

= 1255.8 J

Consequently;

= 1406 x specific heat = 1255.8


Specific heat thus calculated = 0.893 J/g°C


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