Solution:
/ Em₀ = 0.30
Explanation:
In this problem, we apply the connection between mechanical energy, kinetic energy, and gravitational potential energy.
K = ½ m v²
U = mgh
We assess the mechanical energy at two positions:
Initial. Lower
Em₀ = K = ½ m v²
At its highest point
= U = mg and
Now let's compute
Em₀ = ½ m 3.6²
Em₀ = m 6.48
= m 9.8 × 0.2
= m 1.96
Thus the energy lost is given by:
/ Em₀ = m 1.96 / m 6.48
/ Em₀ = 0.30
This means that 30% of the sun's energy is transformed into potential energy.
There are various conversion possibilities.
This energy changes into thermal energy affecting the spores and air, since it cannot be regained.
Answer:
20.353125 V
Explanation:
m = Mass of proton =
q = Charge of proton =
= Velocity of proton at point A = 50 km/s
= Velocity of proton at point B = 80 km/s
The relationship derived from energy conservation is as follows:
The determined potential difference is 20.353125 V
Answer:
a)
b)
c)
Explanation:
According to the problem, the distance from the building where the ball hits is 16m, and its final elevation exceeds the initial height by 8m.
With this information, we can compute the ball’s starting speed.
a) Let's first assess the horizontal trajectory.
(1)
This gives us our initial equation.
Next, we need to examine the vertical trajectory.
Utilizing in our first equation (1)
Now let’s solve for t.
The ball takes two seconds to reach the adjacent building, allowing us to compute its initial speed.
b) To determine the velocity magnitude just before impact, we must calculate both x and y components.
The computed velocity magnitude is:
c) The ball's angle is:
Answer: small barrel gun
Explanation:
It is noted that short barrel guns have a higher muzzle velocity for bullets compared to longer barrel guns.
Acceleration is determined by the change in velocity with respect to time.
For short barrel guns, the bullet reaches its muzzle velocity more quickly, leading to greater acceleration than that of bullets from long barrel guns.