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Andrew
16 days ago
5

Usain Bolt's world-record 100 m sprint on August 16, 2009, has been analyzed in detail. At the start of the race, the 94.0 kg Bo

lt accelerated from rest at a rate of 9.50 m/s2 for the first 0.890 s, and eventually reached a top speed of 12.4 m/s by exerting an average horizontal force of 820 N against the ground for the entire 9.58 s duration of the race.What was the average horizontal force (in N) exerted by Bolt against the ground during the first 0.890 s of the race?
Physics
1 answer:
inna [3.1K]16 days ago
3 0
893 Newtons. The mass of Usain Bolt is 94 kg, and his acceleration in the first 0.89 seconds is 9.5 m/s². According to Newton's Second Law, the average horizontal force that Bolt exerted against the ground in that first 0.890 seconds is 893 Newtons.
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The Hall effect can be used to calculate the charge-carrier number density in a conductor. If a conductor carrying a current of
kicyunya [3294]

Answer:

6.6*10^{27}e/m^3

Explanation:

When calculating Hall voltage, it is crucial to have the current, magnetic field strength, length, area, and number of charge carriers available. The Hall voltage can be expressed using the equation:

V_h = \frac{iB}{neL}

Where:

i= the current

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L = the length

n = the number of charge carriers

e= charge of an electron

We need to replace values and solve for n:

n= \frac{iB}{V_h e L}

n= \frac{2*1.2}{4.5*10^{-6}*5^10^{-3}*1.6*10^{-19}}

n= 6.6*10^{27}electron.m^{-3}

As a result, the charge carrier density is 6.6*10^{27}e/m^3

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1 month ago
A girl drops a pebble from a high cliff into a lake far below. She sees the splash of the pebble hitting the water 2.00s later.
Yuliya22 [3333]

Answer:

19.62 ms

Explanation:

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u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (we take downward direction as positive)

v=u+at\\\Rightarrow v=0+9.81\times 2\\\Rightarrow v=19.62\ m/sUsing the equations of motion

The pebble's speed upon contact with the water is 19.62 ms

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16 days ago
A sinusoidal electromagnetic wave of frequency 6.10×1014hz travels in vacuum in the +x direction. the magnetic field is parallel
Yuliya22 [3333]
Part a) The connection between the electric field and the magnetic field in an electromagnetic wave is
E=cB
where
E signifies the strength of the electric field
B indicates the strength of the magnetic field
c represents the speed of light
Using the equation, we determine:
E=cB=(3 \cdot 10^8 m/s)(5.80 \cdot 10^{-4} T)=1.74 \cdot 10^5 N/C

Part b) The text does not clarify the orientation of the magnetic field on the y-axis: I speculate it points in the y+ direction.
The direction of the electric field can be established using the right-hand rule, which states:
- the index finger shows the direction of E
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Because the wave propagates in the x+ direction, and the magnetic field in the y+ direction, we conclude that the electric field direction (index finger) must be z-.
7 0
1 month ago
Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of
Softa [3030]

ke prop to v^2

ke1/v1^2=ke2/v2^2

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7 0
26 days ago
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kicyunya [3294]

Answer:

Explanation:

Let T represent the tension in the swing.

At the peak mg-T=\frac{mv^2}{r}

where v denotes the velocity needed to maintain the circular motion.

r equals the distance from the rotation point to the center of the ball, which is L+\frac{d}{2} (with d being the ball's diameter).

The threshold velocity can be expressed as mg-0=\frac{mv^2}{r}

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v_0^2=5gr

v_0=\sqrt{5gr}

v_0=\sqrt{5g\left ( \frac{d}{2}+L\right )}

6 0
1 month ago
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