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8090
20 days ago
6

How many fluorine atoms are present in 5.85 g of c2f4?

Chemistry
1 answer:
eduard [2.6K]20 days ago
4 0
The molar mass of C2F4 (tetrafluoroethylene) is 100 g/mol. To find the number of moles of C2F4 in the specified quantity,
n = (5.85 g) / (100 g/mol) = 0.0585 mols C2F4
The calculation for the number of molecules per mole is done via the equation,
(0.0585 mols) x (6.022 x 10^23)
Given that each molecule contains 4 F atoms, then,
(0.0585 mols) x (6.022 x 10^23)(4)
= 1.41 x 10^23 atoms of F
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"solid potassium iodide decomposes into iodine gas and solid potassium. Write a a balanced chemical equation for this reaction"
Alekssandra [2891]


Now, construct a balanced equation:

2KI (s) ----\ \textgreater \ 2K(s) + I_2 (g)

I_2 exists in its gaseous form as a diatomic molecule.
3 0
1 month ago
A 0.100 m solution of which one of the following solutes will have the highest vapor pressure? A 0.100 m solution of which one o
eduard [2645]
Vapor pressure refers to the force exerted by vapor or gas molecules above the surface of a liquid. It is inversely related to the concentration of solute particles; an increase in solute concentration results in a decrease in vapor pressure, and vice versa. For (a), it dissociates into two particles. In (b), the total count of particles from dissociation becomes 1 + 2, totaling three. For (c), dissociation yields 1 + 3 for a total of four particles. (d) Since sucrose is a covalent compound, it does not break apart into ions, so it remains as one particle. For (e), dissociation results in 1 + 1, equating to two particles.
5 0
6 days ago
A patient needs 40.0 mg of antibiotic per kilogram of body weight each day. If the patient weighs 55 kilograms.
VMariaS [2860]

Response:

2200 mg of antibiotic

Explanation:

The prescribed antibiotic dosage is 40 mg/kg of body weight.

For a patient weighing 55 kg, we calculate the dose of antibiotic as follows:

If we analyze 40/1000000, we can determine antibiotic allocation in kg per kg of weight

= 0.00004 kg of antibiotic for each kilogram

0.00004 multiplied by 55 (to find out the required amount for a 55 kg individual)

= 0.0022 kg

This 0.0022 figure converts to milligrams as follows

0.0022*10^6

= 2200 mg of antibiotic is indicated for a patient weighing 55 kg.

4 0
18 hours ago
One hour of bicycle riding can require 500-900 kcal of energy, depending on the speed, the terrain, and the weight of the racer.
alisha [2865]
145 hours. Explanation: Riding a bicycle for one hour expends 505 kcal of energy. Given that one gram of body fat equals 7.70 kcal, and 1 pound of body fat is equivalent to 454 grams: 1 lb = 454 g; thus, 21 lb = 21 × 454/1 = 9534 g. Moreover, converting 9534 g of body fat gives us 9534 × 7.70 kcal/1 = 73411.8 kcal. If riding for one hour burns 505 kcal, then to lose 73411.8 kcal, it would require 73411.8 kcal x 1 hour/505 kcal = 145 hours.
3 0
13 days ago
1. Bailey wants to find out which frozen solid melts the fastest: soda, gatorade, or orange juice. She pours each of the three l
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First scenario:

IV: soda, gatorade, orange juice, and water

DV: state of the liquids listed above

Control: freezer and ice tray

Second scenario:

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Control: chocolate, cloth type, cloth squares

Third scenario:

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Control: pots and daily water amount for the plant

4 0
1 month ago
Read 2 more answers
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