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slavikrds
1 month ago
14

How many grams of mercury are present in a barometer that holds 6.5mL of mercury? ...?

Chemistry
2 answers:
VMariaS [2.6K]1 month ago
4 0

Final answer: The mass of mercury is 20.15 g.

Explanation:

Density is the measure of mass per unit of volume.

Density=\frac{mass}{Volume}

Known: Mass of bromine =?

Density of bromine= 3.1g/ml

volume of bromine = 6.5 ml

Substituting the values yields:

3.1g/ml=\frac{mass}{6.5ml}

mass=20.15g

Consequently, the mass of bromine concludes at 20.15 g.

alisha [2.7K]1 month ago
3 0
<span>13.6
grams of mercury are present in a barometer that holds
per milliliter.
13.6*6.5 = 88.4</span>
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Details:

The equation to calculate work done is defined as follows.

W = -k \frac{q_{1}q_{2}}{d}

where, k = proportionality constant = 8.99 \times 10^{9} Jm/C^{2}

q_{1} = charge of Mg^{2+} = 3.2 \times 10^{-19} C

q_{2} = charge of O_{2-} = -3.2 \times 10^{-19} C

d = separation distance = 0.45 nm = 0.45 \times 10^{-9} m

Now we will insert the given values into the formula above to compute the work done as follows.

W = -k \frac{q_{1}q_{2}}{d}

= \frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}

= 3.68 \times 10^{-18} J

Thus, we can conclude that the work needed to increase the distance between the two ions to infinity is 3.68 \times 10^{-18} J.

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20 days ago
The equilibrium constant for the reaction sr(s) + mg2+(aq) ⇌ sr2+(aq) + mg(s) is 2.69 × 1012 at 25°c. calculate e o for a cell m
eduard [2509]
Sr(s)+Mg²+(aq)→Sr²+(aq)+Mg(s)
Number of electrons transferred, n=2. Equilibrium constant,
K=2.69×10∧12
ΔG=-2.303RT logK
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8 0
17 days ago
a movable chamber has a volume of 18.5 L (at temperature of 18.5 C) assuming no gas escapes and the pressure remains constant wh
VMariaS [2683]

Answer:

39 ^\circ C

Explanation:

We have:

V₁ = 18.5 L

T₁ = 18.5° C = 273 + 18.5 = 291.5 K

V₂ = 19.8 L

T₂ =?

Pressure remains constant

Applying the ideal gas law

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{18.5}{291.5}=\dfrac{19.8}{T_2}

T_2 = 312 K

T_2 = 312 -273 =39 ^\circ C

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1 month ago
The two-slit diffraction experiment shows how light can be treated as particles and how light waves carry the statistical inform
alisha [2704]

The double-slit experiment serves as a renowned method to exemplify concepts in quantum mechanics. Specifically, it highlights the idea of wave-particle duality. Employing a light wave shows diffraction and interference, which are typical characteristics of wave behavior. Unexpectedly, using an electron beam produces an interference pattern as well, indicating that electrons can exhibit wave-like properties.


Explanation:

The optical phenomenon would nearly resemble, yet be entirely distinct from, that involved with the exploitation of light. Interference and diffraction are the characteristics distinguishing waves from particles: waves can interfere and disperse, whereas particles cannot.

Light curves around obstacles akin to waves, and this bending results in the single-slit diffraction pattern.

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21 day ago
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Answer:

m_{Mg}=30.8mgMg

Explanation:

Greetings,

According to the provided chemical equation, the production of 31.2 mL of hydrogen allows one to calculate its moles using the ideal gas equation as detailed below:

n_{H_2}=\frac{PV}{RT}=\frac{754torr*\frac{1atm}{760torr}*0.0312L}{0.082 \frac{atm*L}{mol*K}*298.15K}=1.27x10^{-3}molH_2

Since the ratio of hydrogen to magnesium is 1:1, its milligrams are derived through the following proportional factor calculation:

m_{Mg}=1.27x10^{-3}molH_2*\frac{1molMg}{1molH_2}*\frac{24.305gMg}{1molMg}*\frac{1000mgMg}{1gMg}\\m_{Mg}=30.8mgMg

Regards.

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26 days ago
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