How many grams of mercury are present in a barometer that holds 6.5mL of mercury? ...?

Respuesta:

737.52 mL de agua

Justificación:

En este escenario, es necesario aplicar la fórmula de molaridad de una solución, que es:

M = moles / V

Donde:

V: Volumen de la solución.

Ya que deseamos determinar la cantidad de agua, en otras palabras, buscamos el volumen del solvente que se utilizó para crear los 800 mL de la disolución.

Una disolución se compone de un soluto y un solvente. El soluto que tenemos es nitrato de plata. Utilizando la fórmula mencionada, calculamos los moles de soluto y luego su masa. Tras eso, calculamos el volumen a partir de la densidad y, al final, determinamos la cantidad de solvente de esta manera:

V ste = Vsol - Vsto

Primero, vamos a calcular los moles de soluto:

moles = M * V

moles = 2 * 0.800 = 1.6 moles

Con este número de moles, obtenemos la masa utilizando el peso molecular que es 169.87 g/mol:

m = moles * PM

m = 1.6 * 169.87 = 271.792 g

Usando el valor de densidad, procederemos a calcular el volumen de soluto utilizado:

d = m/V

V = m/d

V = 271.792 / 4.35

V = 62.48 mL

Por último, la cantidad de agua requerida es:

V agua = 800 - 62.48

V agua = 737.52 mL

Calculation yields 209.53. The molar concentration is calculated by moles divided by volume. Given the volume of 750 mL, which translates to 0.75 L, the moles of CuBr₂ can be determined as molar concentration multiplied by volume, resulting in 1.25 × 0.75 = 0.9375. Mole count is derived from the mass of CuBr₂ divided by its molecular mass. The molecular mass of CuBr₂ is computed as 63.5 + 80 × 2 = 223.5, where the mass of Cu is 63.5 and that of Br is 80. Consequently, the mass needed amounts to 223.5 × 0.9375 = 209.53 g.

The coefficients in a balanced equation indicate the relationship between the moles of reactants and products. In this case, four moles of hydrochloric acid react with one mole of oxygen to yield two moles of chlorine and water. Therefore, the mole ratio of hydrochloric acid to chlorine is 2:1. To calculate the number of moles, you divide the mass by the mass of a single mole. Cl2 = 2 * 35.45 = 70.9 grams. Thus, Number of moles = 335 ÷ 70.9, which is roughly 4.72 moles. The amount of hydrochloric acid would then be double that figure.

Answer:

a. the temperature changes will be identical

Explanation:

Dissolving sodium hydroxide (NaOH) in water is an exothermic process, with the heat released calculated using:

Q = m×C×ΔT

Where Q indicates the heat released, m refers to the mass of the solution, C is the specific heat, and ΔH stands for temperature change.

The specific heat of both solutions remains the same (because both are the same solutions). Specific heat = C.

m denotes the mass of the solutions: 102g for experiment 1 and 204g for experiment 2.

The heat released, Q: If 2g releases X heat, then 4g releases 2X.

Thus, the temperature change for each experiment is:

Experiment 1:

X / 102C = ΔT

Experiment 2:

2X / 204C = ΔT

X / 102C = ΔT

Indicating that,

a. the temperature changes will be identical