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olga2289
7 days ago
14

If the tip of the syringe, "The Titrator", was not filled with NaOH before the initial volume reading was recorded, would the co

ncentration of acetic acid in vinegar of that trial be greater than or less than the actual concentration? Please explain your answer.
Chemistry
1 answer:
Anarel [2.7K]7 days ago
6 0

Answer:

The trial's estimated concentration of acetic acid in the vinegar would be higher than the true concentration.

Detailed explanation:

"The titrator" holds the base solution (NaOH) that will be used to titrate the vinegar solution (acetic acid).

If we assume that the syringe tip was not primed prior to recording the initial volume, a portion of the base solution that is released will be retained in the tip of the syringe, resulting in the actual volume of base added to the acetic acid being less than calculated based on the readings.

Consequently, in the calculations, a larger volume of the base is used than what was genuinely applied, which leads to an inflated number of moles of base compared to the actual amount utilized.

Thus, at the point of neutralization, where the equivalents of base equal the equivalents of acid, you will report a higher amount of acid equivalents, resulting in a calculated concentration that is greater than the true concentration. This ultimately means the concentration of acetic acid in the vinegar of that trial would be greater than the actual concentration.

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lions [2782]
I believe you mean KO2 reacting with H2O. The reaction is 4KO2+2H2O->4KOH +3O2. The mole ratio O2:KO2 is 3:4. Thus moles of O2 produced = 0.500/4*3 = 0.375 mol.
6 0
9 days ago
Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. G
Anarel [2728]
1) The chemical equation is

Cu + 2AgNO3 ---> Cu (NO3)2 + 2Ag

2) Molar ratios are as follows:

1 mol Cu: 2 moles AgNO3: 1 mol Cu (NO3)2: 2 mol Ag

3) Converting 12.83 * 10^23 atoms of Cu to moles gives:

12.83 * 10^23 atoms / (6.02 * 10^23 atoms / mol) = 2.131 mol Cu

4) Using the ratios:

2.131 mol Cu * 2 mol Ag / 1 mol Cu = 4.262 mol Ag

5) To convert 4.262 mol of silver to grams, use the atomic weight of silver:

mass = moles × atomic mass = 4.262 mol * 107.9 g / mol = 459.9 grams

Answer: 459.9 g
5 0
29 days ago
The value of delta G at 141.0 degrees celsius for the formation of phosphorous trichloride from its constituent elements,
VMariaS [2860]
The appropriate answer is option E. Gibbs free energy can be expressed using the equation: ΔG = ΔH - TΔS, where ΔH denotes the change in enthalpy of the reaction, T is the reaction temperature, and ΔS signifies entropy change. For our calculations, we have ΔH = -720.5 kJ/mol which converts to -720500 J/mol (given that 1 kJ = 1000 J), ΔS = -263.7 J/K, and T = 141.0°C, which equals 414.15 K. Consequently, the Gibbs free energy for the specified reaction at 141.0°C is calculated as -611.3 kJ/mol.
6 0
14 days ago
For each reaction, identify the element that gets reduced and the element that gets oxidized. 2AgCl+Zn⟶2Ag+ZnCl2 Identify the el
KiRa [2857]

Answer:

Explanation:

The oxidation state corresponds to the charge of each atomic ion. An increase indicates oxidation of the element while a decrease reflects reduction of the element.

2AgCl+Zn⟶2Ag+ZnCl2

Zinc undergoes oxidation, while Ag experiences reduction.

Ag⁺ changes to Ag (oxidation state decreases), thus Ag is reduced.

Zn alters to Zn⁺² (oxidation state increases), hence Zn is oxidized.

4NH₃+3O₂⟶2N₂+6H₂O

The oxidation state of nitrogen in ammonia is -3

whereas it is zero in elemental nitrogen.

An increase in the oxidation state indicates nitrogen is oxidized.

The oxidation state of oxygen is zero when in molecular oxygen and -2 when in water. Therefore, the oxidation state decreases, indicating oxidation is reduced.

Fe₂O₃+2Al⟶Al₂O₃+2Fe

The oxidation state of Fe in Fe₂O₃ is +3, switching to zero in Fe, so iron is reduced.

Aluminum's oxidation state is zero in Al, rising to +3 in Al₂O₃, indicating it is oxidized.

7 0
13 days ago
(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo
castortr0y [2916]

Answer:

La masa molar del compuesto es: 168.82 g/mol

La masa molar del gas es: 16.38 g/mol

Explanation:

(a)

Utilizando la ecuación de gases ideales:

PV=nRT

donde,

P es la presión

V es el volumen

n es el número de moles

T es la temperatura

R es la constante de los gases, cuyo valor es = 0.0821 L.atm/K.mol

Además,

Moles = masa (m) / Masa molar (M)

La densidad (d) = Masa (m) / Volumen (V)

Así, la ecuación de gases ideales se puede expresar como:

PM=dRt

Dado que:-

Presión = 20 kPa = 20000 Pa

La expresión para la conversión de presión en Pascal a presión en atm se muestra a continuación:

P (Pa) = \frac {1}{101325} P (atm)

20000 Pa = \frac {20000}{101325} atm

Presión = 0.1974 atm

Temperatura = 330 K

d = 1.23 kg/m³ = 1.23 g/L

Masa molar =?

Aplica la fórmula:

0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K

⇒M = 168.82 g/mol

La masa molar del compuesto es: 168.82 g/mol

(b)

Dado que:

Presión = 152 Torr

Temperatura = 298 K

Volumen = 250 cm³ = 0.25 L

Utilizando la ecuación de gases ideales:

PV=nRT

R = 62.3637\text{torr}mol^{-1}K^{-1}

Aplicando la fórmula:

152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K

⇒n = 0.002045 moles

Dado que:

Masa del gas = 33.5 mg = 0.0335 g

Masa molar =?

La fórmula para calcular los moles se muestra a continuación:

moles = \frac{Mass\ taken}{Molar\ mass}

Así,

0.002045\ moles
= \frac{0.0335\ g}{Molar\ mass}

La masa molar del gas es: 16.38 g/mol

5 0
1 month ago
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