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hichkok12
27 days ago
14

Magnesium metal burns with a bright white flame. What conclusions can you draw about the electron transitions that can take plac

e for a magnesium atom ?
Chemistry
1 answer:
alisha [2.7K]27 days ago
3 0

Different wavelengths are involved.

Explanation:

When magnesium ignites with a bright white flame, it indicates that various wavelengths are related to the electron transitions occurring in the magnesium atom.

  • Upon combustion, the electrons within the atom become excited.
  • They emit characteristic light that corresponds to their energy levels.
  • White light consists of a mix of different wavelengths.
  • Seeing white light implies that multiple wavelengths combined are responsible for the observed emission.

Learn more:

Spectrum

You might be interested in
Which of the following reactions is a redox reaction? (a) K2CrO4 + BaCl2 → BaCrO4 + 2KCl (b) Pb2+ + 2Br- → PbBr2 (c) Cu + S → Cu
castortr0y [2743]

(c) Cu + S → CuS is classified as a redox reaction

Explanation:

The following reactions are presented:

(a) K₂CrO₄ + BaCl₂ → BaCrO₄ + 2 KCl

(b) Pb²⁺ + 2 Br⁻ → PbBr₂

(c) Cu + S → CuS

Reaction (c) represents a redox reaction, as the oxidation states of the elements are changing. In this case:

Cu + S → CuS

In its elemental form, Cu has an oxidation state of 0, while in CuS (copper sulfide), its oxidation state changes to +2.

Similarly, S in its elemental form has an oxidation state of 0 and is -2 in CuS (copper sulfide).

Learn more about:

redox reactions

7 0
1 month ago
he population of the Earth is roughly eight billion people. If all free electrons contained in this extension cord are evenly sp
eduard [2509]

1) Drift velocity: 3.32\cdot 10^{-4}m/s

2. 5.6\cdot 10^{13} electrons per individual

Explanation:

1)

In a conducting material with an electric current, the drift velocity of electrons can be calculated using this equation:

v_d=\frac{I}{neA}

where

I stands for current

n represents the density of free electrons

e=1.6\cdot 10^{-19}C indicates the charge of an electron

A signifies the wire's cross-sectional area

The wire's cross-sectional area can be determined as

A=\pi r^2

where r denotes the wire's radius. Thus, the equation transforms to

v_d=\frac{I}{ne\pi r^2}

In this scenario, we have:

I = 8.0 A as the current

8.5\cdot 10^{28} m^{-3} indicates the free electron concentration

d = 1.5 mm is the diameter, making the radius

r = 1.5/2 = 0.75 mm = 0.75\cdot 10^{-3}m

So, the resulting drift velocity is:

v_d=\frac{8.0}{(8.5\cdot 10^{28})(1.6\cdot 10^{-19})\pi(0.75\cdot 10^{-3})^2}=3.32\cdot 10^{-4}m/s

2)

The entire length of the cord is

L = 3.00 m

And the cross-sectional area is

A=\pi r^2=\pi (0.75\cdot 10^{-3})^2=1.77\cdot 10^{-6} m^2

Consequently, the volume of the cord is

V=AL (1)

The number of electrons per unit volume is n, thus the total electrons in this cord would be

N=nV=nAL=(8.5\cdot 10^{28})(1.77\cdot 10^{-6})(3.0)=4.5\cdot 10^{23}

Overall, the Earth's population rounds to 8 billion individuals, equating to

N'=8\cdot 10^9

Hence, the number of electrons distributed to each person is:

N_e = \frac{N}{N'}=\frac{4.5\cdot 10^{23}}{8\cdot 10^9}=5.6\cdot 10^{13}

7 0
1 month ago
Which statement best describes the direction of heat flow by conduction between two samples of the same material?
VMariaS [2690]

Response: 2. When molecules with different speeds collide, heat is transferred from the faster ones to the slower ones.

Clarification: I hope this was useful!:)

6 0
10 days ago
Read 2 more answers
The symbol for xenon (Xe) would be a part of the noble gas notation for the element antimony. cesium. radium. uranium.
castortr0y [2743]
Noble gas notation serves as a condensed form of indicating electron configurations. This notation employs the symbol for the preceding noble gas in the electron configuration of an element. For antimony, the noble gas prior is Kr, which means Xe is not used in its electron configuration. Similarly, for radium, the prior noble gas is Rn, whereas, for uranium, it is also Rn. However, for cesium, the preceding noble gas is Xe, thus it is utilized in the noble gas notation for Sb, specifically written as: Cs: [Xe] 6s.

Answer: cesium



8 0
1 month ago
Read 2 more answers
The production of NOx gases is an unwanted side reaction of the main engine combustion process that turns octane, C8H18, into CO
lorasvet [2515]

Answer:

710.33 g NO2

Explanation:

2 C8H18 + 25 O2 → 16 CO2 + 18 H2O  

(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 utilized for combusting octane

87.54 mol O2 x \frac{15}{85} = 15.44 mol O2 used for generating NO2

O2 + 2NO → 2NO2

(15.44 mol O2) x (2/2) x (46.0056 g NO2/mol) = 710.33 g NO2

4 0
11 days ago
Read 2 more answers
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